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Bunuel
If \(10^a * 3^b * 5^c = 450^n\), what is the value of c?

(1) a is 1.
(2) b is 2.



5^a * 2^a * 3^b * 5^c = 5^2n * 3^2n * 2^n ( 450 = 15 * 6 * 5 )

5^a+c = 5^2n => a+c = 2n --1

2^a = 2^n => a = n --2

3^b = 3^2n => b = 2n --3..

Stat 1 : a = 1.. then

From eq 2 : a = n i.e. n =1.. sub this value in eq 1 we get c = 1...Sufficient.

Stat 2: b = 2n , given b = 2. then n = 2 in eq 1 we get c =1...Sufficient.

IMO D is correct answer...
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I think something is wrong with OA no?

From statement 1, it is sufficient to get the value of n, same goes for statement 2:S
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Bunuel
If \(10^a * 3^b * 5^c = 450^n\), what is the value of c?

(1) a is 1.
(2) b is 2.

\(10^a * 3^b * 5^c = 450^n\)
i.e. \(2^a * 3^b * 5^{(a+c)} = 2^n * 3^{2n} * 5^{2n}\)
i.e (a+c) = 2n and a=n and b=2n
i.e. c = 2n-n= n

Question : c = ? i.e. n=?

Statement 1: a is 1
i.e. n = 1 = c
SUFFICIENT


Statement 2: b is 2
i.e. b = 2n = 2
i.e. n = 1 = c
SUFFICIENT

Answer: option D
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Bunuel
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Bunuel
If \(10^a * 3^b * 5^c = 450^n\), what is the value of c?

(1) a is 1.
(2) b is 2.

\(10^a * 3^b * 5^c = 450^n\)
i.e. \(2^a * 3^b * 5^{(a+c)} = 2^n * 3^{2n} * 5^{2n}\)
i.e (a+c) = 2n and a=n and b=2n
i.e. c = 2n-n= n

Question : c = ? i.e. n=?

Statement 1: a is 1
i.e. n = 1 = c
SUFFICIENT


Statement 2: b is 2
i.e. b = 2n = 2
i.e. n = 1 = c
SUFFICIENT

Answer: option D

The correct answer is E here because we don't know whether n is a positive integer or not.

Bunuel Could you please post the official solution of this question???
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GMATinsight
Bunuel
GMATinsight


\(10^a * 3^b * 5^c = 450^n\)
i.e. \(2^a * 3^b * 5^{(a+c)} = 2^n * 3^{2n} * 5^{2n}\)
i.e (a+c) = 2n and a=n and b=2n
i.e. c = 2n-n= n

Question : c = ? i.e. n=?

Statement 1: a is 1
i.e. n = 1 = c
SUFFICIENT


Statement 2: b is 2
i.e. b = 2n = 2
i.e. n = 1 = c
SUFFICIENT

Answer: option D

The correct answer is E here because we don't know whether c and n are positive integers or not.

Bunuel Could you please post the official solution of this question???

We are given \(10^a * 3^b * 5^c = 450^n\).

For (1)+(2) we know that a = 1 and b = 2 --> \(10 * 3^2 * 5^c = 450^n\). Now, for any n, there would exist corresponding c (not necessarily 1) which would make this equation hold. For example, if n = 2, then c = (log(2)+2 log(3)+3 log(5))/(log(5)) ≈ 4.7959
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The correct answer is E here because we don't know whether c and n are positive integers or not.[/quote]

Bunuel Could you please post the official solution of this question???[/quote]

We are given \(10^a * 3^b * 5^c = 450^n\).

For (1)+(2) we know that a = 1 and b = 2 --> \(10 * 3^2 * 5^c = 450^n\). Now, for any n, there would exist corresponding c (not necessarily 1) which would make this equation hold. For example, if n = 2, then c = (log(2)+2 log(3)+3 log(5))/(log(5)) ≈ 4.7959[/quote]


How did you get the log expression from the actual one.. I'm confused
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sai897
The correct answer is E here because we don't know whether c and n are positive integers or not.

Bunuel Could you please post the official solution of this question???[/quote]

We are given \(10^a * 3^b * 5^c = 450^n\).

For (1)+(2) we know that a = 1 and b = 2 --> \(10 * 3^2 * 5^c = 450^n\). Now, for any n, there would exist corresponding c (not necessarily 1) which would make this equation hold. For example, if n = 2, then c = (log(2)+2 log(3)+3 log(5))/(log(5)) ≈ 4.7959[/quote]


How did you get the log expression from the actual one.. I'm confused[/quote]

It does not matter at all. The point is that for for any n, there would exist corresponding c (not necessarily 1) which would make this equation hold.
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Bunuel
If \(10^a * 3^b * 5^c = 450^n\), what is the value of c?

(1) a is 1.
(2) b is 2.

\(10^a * 3^b * 5^c = 450^n\)
i.e. \(2^a * 3^b * 5^{(a+c)} = 2^n * 3^{2n} * 5^{2n}\)
i.e (a+c) = 2n and a=n and b=2n
i.e. c = 2n-n= n

Question : c = ? i.e. n=?

Statement 1: a is 1
i.e. n = 1 = c
SUFFICIENT


Statement 2: b is 2
i.e. b = 2n = 2
i.e. n = 1 = c
SUFFICIENT

Answer: option D
GMATinsight,
How did you get the red part brother?
In red part, if you say a=n, then i'll say a=2n. Then the result will be like below.
-->c = 2n-2n
-->c=0
Without statement 1 and 2, you already get your value C=0........interesting! :)
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Don't like this question one bit, but here are the flawed assumptions we're all making:

Assumption 1) that c and n are integers
Assumption 2) that c and n are positive

Given both statement 1 and statement 2, we are likely to conclude that c = 1, implying n = 1. However, in the unlikely, but possible event that n or c are negative or not integers, we are incorrect.

I prefer the scenario where n is 2 and c is ~4.795889.

This was pointed out earlier using the log function. Since we cannot arrive at a single answer choice, the answer is E.

This problem is to demonstrate integer constraints, not necessarily algebra.

Posted from my mobile device
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Bunuel
If \(10^a * 3^b * 5^c = 450^n\), what is the value of c?

(1) a is 1.
(2) b is 2.

Good one.
Take an example: \(2^c = 825\)
If 'c' is an integer, there will be no value for 'c' which will satisfy the above equation
But, if 'c' is not an integer, there will always be a value for 'c' - a power - which will satisfy the equation given above.

\(2^c = 825\)

\(c = \frac{log 825}{log 2}\)

c = ~9.68825
Hence 2^(9.68825) = 824.99

Hence both statements together are not enough.
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I solved it this way and selected D which is not the correct answer.

2^a * 5^(a+c) * 3^b = (2^1 *5^2 *3^2)^n
2^a * 5^(a+c) * 3^b= 2^n * 5^2n * 3^2n

So I inferred that:
1) a=n
2) a+c= 2n
3) b=2n

So c=n
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Prime factorization of 450 = 2* 3^2 * 5^2
450^n = 2^n * 3^2n * 5^2n
Since 10^a * 3^b * 5^c = 450^n
=> 10^a * 3^b * 5^c = 2^n * 3^2n * 5^2n
=> 2^a * 3^b * 5^(a+c) = 2^n * 3^2n * 5^2n

(1) a is 1.
Equating the powers of 2 on both sides
we get a=n=1
Now equating the powers of 5 on both sides ,
a+c = 2n
=> 1+c = 2*1 = 2
=> c = 1

If n = 1. When Statement 1 gives you that a = 1,
we get 10^1 * 3^b * 5^c = 450^1
=>3^b * 5^c = 45
Value of c depends on value of b . b need not be an integer here .
Not sufficient

(2) b is 2.
Equating the powers of 3 on both sides
2= 2n
=> n = 1
If n = 1, a = 1 .
Now equating the power of 5 on both sides ,
a + c = 2n
=>1 + c = 2
=>c = 1

10^a * 5^c = 50
However , as in statement 1 , c can take infinite values depending on value of a .

Not sufficient
Answer E
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Bunuel
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Bunuel
If \(10^a * 3^b * 5^c = 450^n\), what is the value of c?

(1) a is 1.
(2) b is 2.

\(10^a * 3^b * 5^c = 450^n\)
i.e. \(2^a * 3^b * 5^{(a+c)} = 2^n * 3^{2n} * 5^{2n}\)
i.e (a+c) = 2n and a=n and b=2n
i.e. c = 2n-n= n

Question : c = ? i.e. n=?

Statement 1: a is 1
i.e. n = 1 = c
SUFFICIENT


Statement 2: b is 2
i.e. b = 2n = 2
i.e. n = 1 = c
SUFFICIENT

Answer: option D

The correct answer is E here because we don't know whether c and n are positive integers or not.

If we were given "n" is positive, then were we good to go with (D)?
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