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505-555 (Easy)|   Fractions and Ratios|                  
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calreg11
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Bunuel
calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.

You can solve this question if you look at it conceptually: if the two numbers are 3 and 4 then adding 5 to each number will have a huge impact on the ratio but if the two numbers are 3,000,000 and 4,000,000 then adding 5 to each number will have very little impact on the ratio. So, the new ratio cannot be determined from the information given.

Answer: E.


Bunuel do you think that such question could still appear during the exam ?? just to know
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calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.

You can solve this question if you look at it conceptually: if the two numbers are 3 and 4 then adding 5 to each number will have a huge impact on the ratio but if the two numbers are 3,000,000 and 4,000,000 then adding 5 to each number will have very little impact on the ratio. So, the new ratio cannot be determined from the information given.

Answer: E.


Bunuel do you think that such question could still appear during the exam ??

Hard to say...

Are you asking because of option E?
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Yes. Basically I know that when you encounter a question where option E is among, then it is never the answer (or at least this is the common place)

the reason is that : iof gmat ask you a question says "is impossible to answer" could be to simple, so a trap answer......for this reason I am asking your opinion about.
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Yes. Basically I know that when you encounter a question where option E is among, then it is never the answer (or at least this is the common place)

the reason is that : iof gmat ask you a question says "is impossible to answer" could be to simple, so a trap answer......for this reason I am asking your opinion about.

This question is marked as 'from Official guide' though.
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calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.


I have a small doubt :

Cant the answer be 2 .

As if we originally take the numbers 3 and 4 which satisfies the ratio of 2 quantities be 3:4 and the ratio of increased quantities be 8/9.

I was trying to solve the question without reading the answer choices ans when I find out I cannot solve it . I try to follow hit and trial and 8/9 is there in the options and answered B.

Can any one clear this please ?

Regards,
Abhinav

580 to 700 + in one month difficult but not impossible
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abhinav11
calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.


I have a small doubt :

Cant the answer be 2 .

As if we originally take the numbers 3 and 4 which satisfies the ratio of 2 quantities be 3:4 and the ratio of increased quantities be 8/9.

I was trying to solve the question without reading the answer choices ans when I find out I cannot solve it . I try to follow hit and trial and 8/9 is there in the options and answered B.

Can any one clear this please ?

Regards,
Abhinav

580 to 700 + in one month difficult but not impossible

But if the numbers are different, say 6 and 8, then the new ratio will also be different. Thus you cannot say for sure that the numbers are 3 and 4. Check here a solution: the-ratio-of-two-quantities-is-3-to-4-if-each-of-the-129569.html#p1064455
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Say the quantities are 3x & 4x

There ratio would be \(\frac{3x}{4x} = \frac{3}{4}\)

After adding 5 to each, new ratio is

\(\frac{3x+5}{4x+5}\)

Answer = E
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Hey,

I also started in the same way as Paresh, but giving different values to the quantities; I then tried to find the actual quantities, like this:

x/y = 3/4
4x=3y
x=3y/4

Then, the new ratio will be:
(x+5)/(y+5), here I substitued the above value for x:
(3y/4+5) / (y+5)
(3y+20)/(4y+20) since y is in any case y, then we add the same, so the ratio of 3/4 actually corresponds to the quantities.

Then, if we add 5 to each it would be 8/9.

I don't know if this makes any sense at all. But, we know that the 2 quantities cannot be the same. So, why are we using the same values (let's say x) above?
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pacifist85
Hey,

I also started in the same way as Paresh, but giving different values to the quantities; I then tried to find the actual quantities, like this:

x/y = 3/4
4x=3y
x=3y/4

Then, the new ratio will be:
(x+5)/(y+5), here I substitued the above value for x:
(3y/4+5) / (y+5)
(3y+20)/(4y+20) since y is in any case y, then we add the same, so the ratio of 3/4 actually corresponds to the quantities.

Then, if we add 5 to each it would be 8/9.

I don't know if this makes any sense at all. But, we know that the 2 quantities cannot be the same. So, why are we using the same values (let's say x) above?

Ratios are pure numeric. For example, the ratio of 4 kg mangoes to 8 kg oranges = 1:2

Putting the same variable (as I did) is just for convenience :)
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if this question asks ( both increased by 5 "percent") ......the answer is still E ????? it is confusing !
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calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.
Ratio is NOT the fixed thing-it fluctuates. So, increasing in the ratio can't confirm the fixed value.
Thanks__
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calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.

This is a great question to test your conceptual understanding of RATIOs

Point to note: RATIOs always, always give you a relationship between numbers, they NEVER give you the actual numbers.

Therefore, whenever something is added/subtracted/multiplied/divided to Numerator (Nr) and Denominator (Dr) of a given RATIO, you cannot determine the new RATIO unless you know the actual values of Nr and Dr.

Here, the ratio of two quantities is 3:4. What this actually means is that for every 3 units of Quantity-1 (in Nr), there are 4-units of Quantity-2 (in Dr). So, when you add 5, you have to add it to actual values of Quantity-1 and Quantity-2 to find the new ratio.

Since we do not know the actual values of Quantity-1 and Quantity-2, we can't find the new RATIO after adding 5 to both Nr and Dr.

Hope this helps!
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The ratio of two quantities is 3 to 4.

Suppose quantities are '3' and '4'.

Each of the quantities is increased by 5

=> 3 + 5 = 8 and 4 + 5 = 9

New ratio: 8: 9.

Let's change the quantities now: Suppose quantities are 36 and 48 ( Ratio is still 3:4).

=> 36 + 5 = 41 and 48 + 5 = 53

New ratio: 41: 53.

So, for the given ration 3:4, there is 'n' number of possible combinations. And adding'5' to both will always give a different results.

Answer E.
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Solution



Given
• The ratio of two quantities is 3 to 4.
• Each of the quantities is increased by 5
To find
• The ratio of these two new quantities.

Approach and Working out
• Let the two numbers be 3x and 4x, respectively.
• After the increase, these numbers become 3x + 5 and 4x + 5, respectively.
• Thus, the ratio of these new numbers = (3x + 5)/(4x + 5)
    o We cannot simplify this ratio further. The ratio will depend on the value of x.
       For example, if x = 1, this ratio will be 8/9, while if x = 2, this ratio will be 11/13.
       Hence, we cannot determine a sure ratio from the given information.

Correct Answer: Option E
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calreg11
The ratio of two quantities is 3 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities?

A. 3/4
B. 8/9
C. 18/19
D. 23/24
E. It cannot be determined from the information given.

\(\frac{3x+5}{5x+5}\)

Case I

Let x = 1

So, \(\frac{3x+5}{5x+5}=\frac{8}{10}\)

Case II

Let x = 2

So, \(\frac{3x+5}{5x+5}=\frac{11}{15}\)

Thus, no specific/unique value is possible, hence Answer must be (E)
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