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What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2

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What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 26 Nov 2017, 22:39
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A
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C
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E

Difficulty:

  45% (medium)

Question Stats:

57% (04:06) correct 43% (00:53) wrong based on 54 sessions

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What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 26 Nov 2017, 22:45
Bunuel wrote:
What is the value of x ?

(1) \(x^3 = 6x − x^2\)

(2) \(14x = x^3 + 5x^2\)



(1)
x^3 = 6x − x^2
x (x^2 + x - 6) = 0
x (x+3) (x-2) = 0..multiple answers not sufficient

(2)
14x = x^3 + 5x^2
x(x^2 + 5x -14) = 0
x(x+7)(x-2) = 0....multiple answers not sufficient

on combining x=0 or 2
Not Sufficient
E
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Thanks
Luckisnoexcuse


Last edited by Luckisnoexcuse on 26 Nov 2017, 22:52, edited 1 time in total.

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Re: What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 26 Nov 2017, 22:49
Bunuel wrote:
What is the value of x ?

(1) \(x^3 = 6x − x^2\)

(2) \(14x = x^3 + 5x^2\)


From Stmnt 1: x(x+3)(X-2) = 0
From Stmnt 2: x(x+7)(x-2) = 0

Combined x= 2,0

Should be E

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Re: What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 11 Dec 2017, 16:53
I got 2 or -3 for (1) and -7 or 2 for (2) so I picked C because x can be 2 in both (1) and (2). Why is that wrong?

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Re: What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 11 Dec 2017, 17:01
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Hi
You have missed the case when x can be zero.
Hence by using both the statements, x can be 0 or 2.
Hence insufficient.
Answer is E.

[the quote="najsh2"]I got 2 or -3 for (1) and -7 or 2 for (2) so I picked C because x can be 2 in both (1) and (2). Why is that wrong?

Posted from my mobile device[/quote]

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Re: What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 11 Dec 2017, 17:02
gmatbusters wrote:
Hi
You have missed the case when x can be zero.
Hence by using both the statements, x can be 0 or 2.
Hence insufficient.
Answer is E.

[the quote="najsh2"]I got 2 or -3 for (1) and -7 or 2 for (2) so I picked C because x can be 2 in both (1) and (2). Why is that wrong?

Posted from my mobile device


Posted from my mobile device[/quote]

Thats what i was missing. Its very clear. Thank you!


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Re: What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2 [#permalink]

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New post 12 Dec 2017, 03:46
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Hi najsh2
If u really like my explanation, please provide me Kudos... ?

najsh2 wrote:
gmatbusters wrote:
Hi
You have missed the case when x can be zero.
Hence by using both the statements, x can be 0 or 2.
Hence insufficient.
Answer is E.

[the quote="najsh2"]I got 2 or -3 for (1) and -7 or 2 for (2) so I picked C because x can be 2 in both (1) and (2). Why is that wrong?

Posted from my mobile device


Posted from my mobile device


Thats what i was missing. Its very clear. Thank you!


Sent from my iPhone using GMAT Club Forum mobile app[/quote]

Posted from my mobile device
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Re: What is the value of x ? (1) x^3 = 6x − x^2 (2) 14x = x^3 + 5x^2   [#permalink] 12 Dec 2017, 03:46
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