Last visit was: 11 Dec 2024, 19:15 It is currently 11 Dec 2024, 19:15
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 11 Dec 2024
Posts: 97,815
Own Kudos:
Given Kudos: 88,242
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,815
Kudos: 685,159
 [18]
1
Kudos
Add Kudos
16
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
nkin
Joined: 09 Jun 2018
Last visit: 25 Jan 2022
Posts: 170
Own Kudos:
461
 [6]
Given Kudos: 86
Location: United States
GMAT 1: 730 Q50 V39
GPA: 4
WE:Operations (Manufacturing)
Products:
5
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
General Discussion
User avatar
dimmak
Joined: 08 Sep 2017
Last visit: 04 Jun 2019
Posts: 54
Own Kudos:
522
 [1]
Given Kudos: 185
Location: Colombia
GMAT 1: 710 Q49 V39
Products:
GMAT 1: 710 Q49 V39
Posts: 54
Kudos: 522
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
dave13
Joined: 09 Mar 2016
Last visit: 23 Nov 2024
Posts: 1,133
Own Kudos:
Given Kudos: 3,851
Posts: 1,133
Kudos: 1,057
Kudos
Add Kudos
Bookmarks
Bookmark this Post
dimmak
Question stem should be: Which of the following points is located...


dimmak - IMO the question is correct. "points" is in plural form :grin:
User avatar
dimmak
Joined: 08 Sep 2017
Last visit: 04 Jun 2019
Posts: 54
Own Kudos:
Given Kudos: 185
Location: Colombia
GMAT 1: 710 Q49 V39
Products:
GMAT 1: 710 Q49 V39
Posts: 54
Kudos: 522
Kudos
Add Kudos
Bookmarks
Bookmark this Post
dave13
dimmak
Question stem should be: Which of the following points is located...


dimmak - IMO the question is correct. "points" is in plural form :grin:

But there is just one point that complies. I mean, if you say "are" it would state that there are more than one point that comply with the statement. And because of the essence of the Problem Solving questions, there is just one answer.
avatar
ankitprad
Joined: 18 Jul 2019
Last visit: 22 Dec 2020
Posts: 35
Own Kudos:
Given Kudos: 128
Posts: 35
Kudos: 41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
nkin
As the line passes through (0,0) and (8,2), the equation of the line is x = 4y or x-4y = 0.
Take (8,3) and substitute: we get 8-4*3 = 8 - 12 = -4 < 0 hence above line
Take (8,1) and substitute: we get 8-4*1 = 8 - 4 = 4 > 0 hence below line.

Also, if a point has to be in the shaded region, it has to be in the third quadrant.
ELIMINATE A,B,E. Only options to check are C and D.

D: (-4,-4), substitute: -4 - (4*-4) = -4 +16 = 12 > 0, so below line in third quadrant. Hence eliminate

C: (-4, -0.5), substitute: -4 - (4*-0.5) = -4 + 2 = -2 < 0, so above line in third quadrant. Hence has to be inside the shaded region.

Hence Option C

Hi,
Could you please tell me if a line passing through the origin has a constant as in the equation of the line y = mx + c is zero meaning c = 0? If that is true, then i understand why the equation of the line in the question will be x-4y=0. Else, could you explain why ?

Thanks
avatar
chiragmaniar
Joined: 28 May 2017
Last visit: 13 May 2020
Posts: 6
Own Kudos:
5
 [2]
Given Kudos: 158
Posts: 6
Kudos: 5
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is how I solved it. The shaded region clearly is in the 3rd Quadrant, so options A, B & E are eliminated.

Since the line passes through the origin, the slope of the line can be determined as follows
2-0 / 8-0 = 1/4

Now, for the point to lie in the shaded region, the slope formed by such point with the point (8,2) has to be less than 1/4, which is the slope of our line.
Now, let's test the points in Options C & D
Option C has (-4, -0.5)
So, slope would be 2-(-0.5) / 8-(-4) = 2.5/12, this is less than 1/4.

Option D has (-4, -4)
So, slope would be 2-(-4) / 8-(-4) = 1/2, this is more than 1/4.

Therefore, our answer is Option C.
User avatar
Subhrajyoti
Joined: 03 Jun 2013
Last visit: 11 Jan 2022
Posts: 72
Own Kudos:
11
 [1]
Given Kudos: 1
Posts: 72
Kudos: 11
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
slope= y2-y1/x2-x1, using the above diagram we will get our slope as 1/4, thus making the equation of our line as 4y=x or 4y-x=0. If we put put the (-4,-0.5) we get 4*(-0.5)-(-4) = 6, then how are we confirming answer choice C, please explain
User avatar
yash1208
Joined: 11 Jun 2022
Last visit: 01 Dec 2022
Posts: 2
Given Kudos: 41
Posts: 2
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ankitprad
nkin
As the line passes through (0,0) and (8,2), the equation of the line is x = 4y or x-4y = 0.
Take (8,3) and substitute: we get 8-4*3 = 8 - 12 = -4 < 0 hence above line
Take (8,1) and substitute: we get 8-4*1 = 8 - 4 = 4 > 0 hence below line.

Also, if a point has to be in the shaded region, it has to be in the third quadrant.
ELIMINATE A,B,E. Only options to check are C and D.

D: (-4,-4), substitute: -4 - (4*-4) = -4 +16 = 12 > 0, so below line in third quadrant. Hence eliminate

C: (-4, -0.5), substitute: -4 - (4*-0.5) = -4 + 2 = -2 < 0, so above line in third quadrant. Hence has to be inside the shaded region.

Hence Option C

Hi,
Could you please tell me if a line passing through the origin has a constant as in the equation of the line y = mx + c is zero meaning c = 0? If that is true, then i understand why the equation of the line in the question will be x-4y=0. Else, could you explain why ?

Thanks

Hi, We know that the line given is passing through the origin hence it will not have a y-intercept (c) or the y-intercept = 0 as the definition of y-intercept is the point where a given line passes through the Y-axis. Since the line intersects the origin, it passes through both X and Y axis at (0,0) making 0 your x and y intercept respectively.

I would like to point out that when the line is in the form y=mx + c, point c is used as it is the y-intercept. However when the line is expressed in the form x=my+ b, point b is used to denote the x - intercept which in this case is also 0 as explained above.

Hope this was helpful.
User avatar
yash1208
Joined: 11 Jun 2022
Last visit: 01 Dec 2022
Posts: 2
Given Kudos: 41
Posts: 2
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Subhrajyoti
slope= y2-y1/x2-x1, using the above diagram we will get our slope as 1/4, thus making the equation of our line as 4y=x or 4y-x=0. If we put put the (-4,-0.5) we get 4*(-0.5)-(-4) = 6, then how are we confirming answer choice C, please explain

Hi Subhrajyoti,
I believe you have used the correct method to find the slope and express the line in slope point form. However, we don't need to substitute to find the answer as the question has asked us to identify the point which lies within the shaded region. To verify that option C (-4,-0.5) does lie in the shaded region, we can substitute any one value of either x or y in the equation.

For example,
Equation: 4y=x
- Substituting x= -4 in the equation
We get 4y=-4
and y= -1

This means that the point (-4,-1) lies on the line and hence the point C (-4,-1) will definitely lie within the shaded region

Hope this helps.
Moderator:
Math Expert
97815 posts