nkin wrote:
As the line passes through (0,0) and (8,2), the equation of the line is x = 4y or x-4y = 0.
Take (8,3) and substitute: we get 8-4*3 = 8 - 12 = -4 < 0 hence above line
Take (8,1) and substitute: we get 8-4*1 = 8 - 4 = 4 > 0 hence below line.
Also, if a point has to be in the shaded region, it has to be in the third quadrant.
ELIMINATE A,B,E. Only options to check are C and D.
D: (-4,-4), substitute: -4 - (4*-4) = -4 +16 = 12 > 0, so below line in third quadrant. Hence eliminate
C: (-4, -0.5), substitute: -4 - (4*-0.5) = -4 + 2 = -2 < 0, so above line in third quadrant. Hence has to be inside the shaded region.
Hence Option C
Hi,
Could you please tell me if a line passing through the origin has a constant as in the equation of the line y = mx + c is zero meaning c = 0? If that is true, then i understand why the equation of the line in the question will be x-4y=0. Else, could you explain why ?
Thanks