ankitprad
nkin
As the line passes through (0,0) and (8,2), the equation of the line is x = 4y or x-4y = 0.
Take (8,3) and substitute: we get 8-4*3 = 8 - 12 = -4 < 0 hence above line
Take (8,1) and substitute: we get 8-4*1 = 8 - 4 = 4 > 0 hence below line.
Also, if a point has to be in the shaded region, it has to be in the third quadrant.
ELIMINATE A,B,E. Only options to check are C and D.
D: (-4,-4), substitute: -4 - (4*-4) = -4 +16 = 12 > 0, so below line in third quadrant. Hence eliminate
C: (-4, -0.5), substitute: -4 - (4*-0.5) = -4 + 2 = -2 < 0, so above line in third quadrant. Hence has to be inside the shaded region.
Hence Option C
Hi,
Could you please tell me if a line passing through the origin has a constant as in the equation of the line y = mx + c is zero meaning c = 0? If that is true, then i understand why the equation of the line in the question will be x-4y=0. Else, could you explain why ?
Thanks
Hi, We know that the line given is passing through the origin hence it will not have a y-intercept (c) or the y-intercept = 0 as the definition of y-intercept is the point where a given line passes through the Y-axis. Since the line intersects the origin, it passes through both X and Y axis at (0,0) making 0 your x and y intercept respectively.
I would like to point out that when the line is in the form y=mx + c, point c is used as it is the y-intercept. However when the line is expressed in the form x=my+ b, point b is used to denote the x - intercept which in this case is also 0 as explained above.
Hope this was helpful.