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nick1816
the first row can be arranged in number of ways= 4C2= 6

after first step...first column can be arranged in = 3C2 ways = 3

It's obvious upto now....What's interesting is to arrange rest 3 by 3 matrix.

it's (1+2C2+2C2). (try to find it)

Total number of ways= 6*3*5= 90





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You are given a 4×4 square Board and you need to fill it with Red and Blue colors such that there are exactly two blue boxes and two red boxes in each row and column. In how many ways is it possible to fill the colors in 4×4 square Board.

A. 12
B. 45
C. 48
D. 90
E. 96

Can you send it's solution?

Posted from my mobile device

nick1816

it's (1+2C2+2C2). (try to find it)

Please elaborate
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Selected 90 based on a guess.
Knew it had to be less that 4!*4 = 96 and more that 4C2*4C2*2C2*2C2*2 = 72

90 is the only one that fits this.

Curious what the actual solution methodology is.
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took educated guess but still took 1 minute 52 second to get 90 .
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Kinshook

I made a typo earlier. It's 2C1.

No. of ways to fill second row is 3C2


Now from these 3 ways,

- - One will lead to complete filled board [ when the colours in first row and second row match ] { 1× 1 }

( because there can be only 2 blocks of same colour in a line )

- - Other two will lead to two cases each [ as on filling the opposite colours, we would go to the leftmost empty block of 3rd row. There we will have 2 colours to fill in, so 2 ways ] { 2C1+2C1 }
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