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chesstitans
Bunuel
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1⁄2 + 1⁄3 + 1⁄4 + 1⁄5 + 1⁄6 = ?

1⁄4
1 1⁄20
1 1⁄4
1 9⁄20
1 29⁄60

Please format questions properly. Thank you.

\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = ?\)


A. \(\frac{11}{4}\)

B. \(1 \frac{1}{20}\)

C. \(1 \frac{1}{4}\)

D. \(1 \frac{9}{20}\)

E. \(1 \frac{29}{60}\)

\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = \frac{30+20+15+12+10}{60} = \frac{87}{60}=\frac{29}{20}=1 \frac{9}{20}\)

pls help, I have 2 questions.
1/ How do I format the question?
2/ Is there a better way to calculate such math problems?

1. Writing Mathematical Formulas on the Forum: https://gmatclub.com/forum/rules-for-po ... l#p1096628

2. Finding common denominator is easiest way. Some questions might have a shortcut solutions but this method will always give you the correct answer.
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chesstitans
\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = ?\)


A. \(\frac{11}{4}\)

B. \(1 \frac{1}{20}\)

C. \(1 \frac{1}{4}\)

D. \(1 \frac{9}{20}\)

E. \(1 \frac{29}{60}\)



Just to make the calculation easier.
remember \(\frac{1}{3}+\frac{1}{6}=\frac{1}{2}\)
\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = \frac{1}{2} + (\frac{1}{3} + \frac{1}{6}) + \frac{1}{5} + \frac{1}{4} = \frac{1}{2} + \frac{1}{2} + \frac{4+5}{5*4} = 1+ \frac{9}{20}\)
D
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chesstitans
\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = ?\)


A. \(\frac{11}{4}\)

B. \(1 \frac{1}{20}\)

C. \(1 \frac{1}{4}\)

D. \(1 \frac{9}{20}\)

E. \(1 \frac{29}{60}\)
-------------------

One possible way of calculation could be:
=(1/2 + 1/3) +1/4 +1/5 + 1/6 (selecting the first 2 as you would get a denominator of 6 which you can quickly combine with the last term, select those with denominators that dont have any common facors i.e. GCD = 1, that will help in quick calculation)
= 5/6 + 1/6 + 1/4 + 1/5
= 1 + (1/4 + 1/5)
= 1 + (9/20)
= 1 9/20
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chesstitans
\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = ?\)


A. \(\frac{11}{4}\)

B. \(1 \frac{1}{20}\)

C. \(1 \frac{1}{4}\)

D. \(1 \frac{9}{20}\)

E. \(1 \frac{29}{60}\)
Using the common denominator is quick; the numerators are not hard to calculate.

\(\frac{30}{60} + \frac{20}{60} + \frac{15}{60} + \frac{12}{60} + \frac{10}{60} =\)

\(\frac{87}{60} = \frac{29}{20} = 1\frac{9}{29}\)

Answer D
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chesstitans
\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = ?\)


A. \(\frac{11}{4}\)

B. \(1 \frac{1}{20}\)

C. \(1 \frac{1}{4}\)

D. \(1 \frac{9}{20}\)

E. \(1 \frac{29}{60}\)

\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6}\)

= \(\frac{30+20+15+12+10}{60}\)

= \(\frac{87}{60}\)

= \(1 \frac{27}{60}\)

= \(1 \frac{9}{20}\)

Thus, answer will be (D)
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Here's a short video of me showing how to solve the problem.

There are two ways to solve this problem.
1) Simplifying the fractions
2) Adding all the fractions (mental math)

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