chesstitans wrote:

\(\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} = ?\)

A. \(\frac{11}{4}\)

B. \(1 \frac{1}{20}\)

C. \(1 \frac{1}{4}\)

D. \(1 \frac{9}{20}\)

E. \(1 \frac{29}{60}\)

Using the common denominator is quick; the numerators are not hard to calculate.

\(\frac{30}{60} + \frac{20}{60} + \frac{15}{60} + \frac{12}{60} + \frac{10}{60} =\)

\(\frac{87}{60} = \frac{29}{20} = 1\frac{9}{29}\)

Answer D

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