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# A professional painter is painting the window frames of an old Victori

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Re: A professional painter is painting the window frames of an old Victori [#permalink]
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In 1st case the ladder was at a distance of from base =sq. rt of 25^2-15^2=sq rt. 400=20

In the 2nd case the ladder was at a distance of from base =sq. rt of 25^2-24^2=sq rt 49=7

so the ladder has moved = 20-7= 13m towards the base.
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Re: A professional painter is painting the window frames of an old Victori [#permalink]
Bunuel wrote:

Tough and Tricky questions: Geometry.

A professional painter is painting the window frames of an old Victorian House. The worker has a ladder that is exactly 25 feet in length which he will use to paint two sets of window frames. To reach the first window frame, he places the ladder so that it rests against the side of the house at a point exactly 15 feet above the ground. When he finishes, he proceeds to reposition the ladder to reach the second window so that now the ladder rests against the side of the house at a point exactly 24 feet above the ground. How much closer to the base of the house has the bottom of the ladder now been moved?

A) 7
B) 9
C) 10
D) 13
E) 27

Kudos for a correct solution.

Source: Chili Hot GMAT

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Re: A professional painter is painting the window frames of an old Victori [#permalink]

$$\sqrt{25^2 - 15^2} - \sqrt{25^2 - 24^2} = \sqrt{40 * 10} - \sqrt{49 * 1} = 20 - 7 = 13$$
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Re: A professional painter is painting the window frames of an old Victori [#permalink]

15 feet high and a 25 feet hypothenuse

a2+b2=c2
a2+b2-c2=0
225+b^2-625=0
b^2=400
sqrt(400) is sqrt of 4 times sqrt of 100
20 feet base

24 feet and a 25 feet hypothenuse

a2+b2=c2
a2+b2-c2=0
576+b^2-625=0
b^2= 49
7 feet base

It moved 13 feet
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Re: A professional painter is painting the window frames of an old Victori [#permalink]
Bunuel wrote:

Tough and Tricky questions: Geometry.

A professional painter is painting the window frames of an old Victorian House. The worker has a ladder that is exactly 25 feet in length which he will use to paint two sets of window frames. To reach the first window frame, he places the ladder so that it rests against the side of the house at a point exactly 15 feet above the ground. When he finishes, he proceeds to reposition the ladder to reach the second window so that now the ladder rests against the side of the house at a point exactly 24 feet above the ground. How much closer to the base of the house has the bottom of the ladder now been moved?

A) 7
B) 9
C) 10
D) 13
E) 27

Kudos for a correct solution.

Source: Chili Hot GMAT

Very easy problem

Attachment:

Ladder.png [ 7.04 KiB | Viewed 3153 times ]

Earlier the ladder was 20m away from window and now it is 7m away from the window , so it comes close to the base of the house by (20 - 7) 13m
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Re: A professional painter is painting the window frames of an old Victori [#permalink]
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Re: A professional painter is painting the window frames of an old Victori [#permalink]
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