anshul2014 wrote:

tgubbay1 wrote:

Hi, Is this a rule? As in; if the squirrel had travelled 1/4 of the distance would he stand 10m above the ground?

hi tgubbay,

It is called

properties of similar triangles i.e if two triangles are similar than their angles are equal and their sides are in proportion suppose c makes a point c1 on ground and b makes a point b1 on ground then ab/bb1= ac/cc1 and the answer to your question is yes b will be 10 just plug in the values in the ratios.

hope it helps

Hi

tgubbay1 - let me explain to you how the ratio of the sides was arrived at.

If you look at the figure, you can observe that in triangle ACE which is a right angled triangle, we can write \(Sin x = \frac{CE}{AC}\)

Similarly, in triangle ABD which is also a right angled triangle, we can write \(Sin x = \frac{BD}{AB}\)

From the above two equations, we can write \(\frac{CE}{AC} = \frac{BD}{AB}\). Since we know that \(AB= \frac{AC}{2}\), we can simplify the expression to \(BD = \frac{CE}{2}\). Thus, to find the value of BD, we need to know the value of CE, which is given to us by st-I.

Hence, had AB been equal to \(\frac{AC}{4}\), BD would also have been equal to \(\frac{CE}{4}\).

Hope it helps!

Regards

Harsh

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