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BillyZ
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Joined: 14 Nov 2016
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GMAT 1: 750 Q51 V40 (Online)
Posts: 1,158
29 Jan 2017, 07:31
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
84% (00:50) correct
16%
(01:02)
wrong
based on 126
sessions
History
Date
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Not Attempted Yet
If \(10\) is the greatest common divisor of positive integers \(x\) and \(y\), and \(20\) is the lowest common multiple of \(x\) and \(y\), what is the value of \(xy\)?
A) 15
B) 20
C) 30
D) 100
E) 200
A) 15
B) 20
C) 30
D) 100
E) 200
29 Jan 2017, 09:31
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ziyuenlau
If \(10\) is the greatest common divisor of positive integers \(x\) and \(y\), and \(20\) is the lowest common multiple of \(x\) and \(y\), what is the value of \(xy\)?
A) 15
B) 20
C) 30
D) 100
E) 200
A) 15
B) 20
C) 30
D) 100
E) 200
NICE RULE: (The greatest common divisor of x and y)(The least common multiple of x and y) = xy
So, for this question, we get: (10)(20) = xy
Evaluate: 200 = xy
Answer:
29 Jan 2017, 09:34
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ziyuenlau
If \(10\) is the greatest common divisor of positive integers \(x\) and \(y\), and \(20\) is the lowest common multiple of \(x\) and \(y\), what is the value of \(xy\)?
A) 15
B) 20
C) 30
D) 100
E) 200
A) 15
B) 20
C) 30
D) 100
E) 200
Alternatively, you might try to come up with values for x and y that satisfy the given information (GCD = 10 AND LCM = 20)
After some fiddling, we might find out that, if x = 10 and y = 20, their GCD is 10 and their LCM = 20)
So, xy = (10)(20) = 200
Answer: E
Cheers,
Brent
