It has to be C because mode and median are unequal in every other set.

A. mode=2 median=2,5
B. mode=2 median=5
D. mode=105 median=103,5
E. mode=51 median=13

In C x+2 and x+3 have the same frequency. median is x+2=mode

Answer C
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Answer = C. [x, x+1, x+2, x+2, x+3, x+3]

Mode = (x+2) & (x+3)

Median \(= \frac{x+2+x+2}{2} = x+2\)

x+2 hold true for both mode & median

OA = C

mode = mean = "x+2"

Ans C

Using PoE, mode and median are unequal in every other set.

VERITAS PREP OFFICIAL SOLUTION

Correct Answer: (C)

The mode is the most common number; the median is the middle number when the numbers are arranged from least to greatest. Any number plus an integer value is greater than the original number, so x + 1 is greater than x, x + 2 is greater than x + 1, etc., so set (C) is arranged from least to greatest. Its median is the average of (x+2) and (x+2), which must be (x+2). (x+2) is also the most common number, so the mode of set C is equal to the median of set C.
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C is the answer as both the median as well as the median are x+2 because there 6 items and the median is 3rd and 4th item sum divided by 2 which is equal to x+2 also the frequency is x+2 and x+3 hence mode is x+2 and x+3 but equal median is x+2 hence it is the answer.

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