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11 Feb 2015, 06:43
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (01:24) correct
23%
(01:29)
wrong
based on 266
sessions
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If the mode of Set A is equal to the median of Set A, Set A could be
A. [0, 1, 2, 2, 3, 4, 5, 6]
B. [2, 2, 5, 7, 9]
C. [x, x+1, x+2, x+2, x+3, x+3]
D. [10, 102, 105, 105]
E. [4, 7, 10, 11, 25/2, 13, 13, 17, 29, 51, 51, 51]
Kudos for a correct solution.
A. [0, 1, 2, 2, 3, 4, 5, 6]
B. [2, 2, 5, 7, 9]
C. [x, x+1, x+2, x+2, x+3, x+3]
D. [10, 102, 105, 105]
E. [4, 7, 10, 11, 25/2, 13, 13, 17, 29, 51, 51, 51]
Kudos for a correct solution.
11 Feb 2015, 07:42
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Bunuel
If the mode of Set A is equal to the median of Set A, Set A could be
A. [0, 1, 2, 2, 3, 4, 5, 6]
B. [2, 2, 5, 7, 9]
C. [x, x+1, x+2, x+2, x+3, x+3]
D. [10, 102, 105, 105]
E. [4, 7, 10, 11, 25/2, 13, 13, 17, 29, 51, 51, 51]
Kudos for a correct solution.
A. [0, 1, 2, 2, 3, 4, 5, 6]
B. [2, 2, 5, 7, 9]
C. [x, x+1, x+2, x+2, x+3, x+3]
D. [10, 102, 105, 105]
E. [4, 7, 10, 11, 25/2, 13, 13, 17, 29, 51, 51, 51]
Kudos for a correct solution.
It has to be C because mode and median are unequal in every other set.
A. mode=2 median=2,5
B. mode=2 median=5
D. mode=105 median=103,5
E. mode=51 median=13
In C x+2 and x+3 have the same frequency. median is x+2=mode
Answer C
11 Feb 2015, 22:30
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Answer = C. [x, x+1, x+2, x+2, x+3, x+3]
Mode = (x+2) & (x+3)
Median \(= \frac{x+2+x+2}{2} = x+2\)
x+2 hold true for both mode & median
Mode = (x+2) & (x+3)
Median \(= \frac{x+2+x+2}{2} = x+2\)
x+2 hold true for both mode & median
