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Re: In order to modernize billing operations, a company bought a total of [#permalink]
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AbdurRakib wrote:
In order to modernize billing operations, a company bought a total of 60 computers and 20 printers. If the price of each computer was three times the price of each printer, what percent of the total cost of the purchase was the cost of one computer and one printer?


A. 2 %

B. \(\frac{7}{2}\) %

C. 4 %

D. \(\frac{2}{3}\)%

E. 12 %


I'm a big fan of the plugging in values approach (demonstrated by the two posters above).
That said, here's an algebraic approach.

Let x = PRICE of 1 printer
So, 3x = PRICE of 1 computer

So, the COST of 20 printers = 20x
And the COST of 60 computers = 60(3x) = 180x

So, the TOTAL cost of 20 printers and 60 computers = 20x + 180x = 200x
The TOTAL cost of 1 printer and 1 computer = x + 3x = 4x

What percent of the total cost of the purchase was the cost of one computer and one printer?
4x/200x = 4/200 = 2/100 = 2%

Answer:

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Re: In order to modernize billing operations, a company bought a total of [#permalink]
AbdurRakib wrote:
In order to modernize billing operations, a company bought a total of 60 computers and 20 printers. If the price of each computer was three times the price of each printer, what percent of the total cost of the purchase was the cost of one computer and one printer?


A. 2 %

B. \(\frac{7}{2}\) %

C. 4 %

D. \(\frac{2}{3}\)%

E. 12 %


Let, Price of printer be 1 & the price of computer is 3

So, the cost price of 60 computers and 20 printers is -

\(60*3 + 20*1\)

\(= 180 + 20\)

\(= 200\)

Quote:
Total cost of the purchase was the cost of one computer and one printer


\(= 3+ 1\)

\(= 4\)

Quote:
what percent of the total cost of the purchase was the cost of one computer and one printer?


\(= \frac{4}{200*100}\)

= \(2%\)

Thus, answer must be (A) 2%
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Re: In order to modernize billing operations, a company bought a total of [#permalink]
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