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Bunuel
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E

We can use the property of Co-primes .
Q: is X prime?
Does X have only 2 factors Viz 1 and itself?
Does X^2 have only 3 factors?

St1. NOT SUFFICIENT
X and Y are consecutive integers-
Property- Consecutive integers have only 1 as a common factor. Hence a pair of consecutive integers is co-prime.
X=2 Y=3 >> X is prime
x=4 y=5 >> X is not a prime

st.2 - NOT SUFFICIENT
LCM OF X anf y =xy

Same property of co primes- use x any y as consecutive integers. You'll get 2 cases. So insufficient

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Solving this by thinking of examples makes sense. Notice that x has to be a positive integer. There is no restriction for x or y to be 1 (non-prime)

(1) GCF of x and y is 1
--> Easiest example is x=1 and y=1 in which case x is not prime. However, if x=2 and y=3 then x is prime. INSUFFICIENT
(2) The LCM of x and y is xy
--> Again, the easiest example would be x=1 and y=1 in which case x is not prime. However, x=2 and y=3 also work, in which case x is prime. INSUFFICIENT

(1)&(2) Since we already tested x=1 and y=1 and x=2 and y=3 in both statements, both together are insufficient, and the answer is E.
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Asked: Is the positive integer x prime?

(1) The Greatest Common Factor of x and y is 1.
GCF(x,y) = 1
x & y are co-prime (no common factor)
If x = 6; y=5; GCF(6,5)=1; But 6 is NOT a prime number
But if x = 3; y=5; GCF(3,5)=1; And 3 is a prime number
NOT SUFFICIENT

(2) The Least Common Multiple of x and y is xy.
LCM(x,y) = xy
x & y are co-prime (no common factor)
If x = 6; y=5; LCM(6,5)=30; But 6 is NOT a prime number
But if x = 3; y=5; LCM(3,5)=15; And 3 is a prime number
NOT SUFFICIENT

(1) + (2)
(1) The Greatest Common Factor of x and y is 1.
(2) The Least Common Multiple of x and y is xy.
x & y are co-prime (no common factor)
If x = 6; y=5; GCF(6,5)=1; LCM(6,5) = 30 But 6 is NOT a prime number
But if x = 3; y=5; GCF(3,5)=1; LCM(3,5) = 15; And 3 is a prime number
NOT SUFFICIENT

IMO E
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