Last visit was: 22 Apr 2026, 20:41 It is currently 22 Apr 2026, 20:41
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
Sub 505 (Easy)|   Combinations|                                       
User avatar
Mehemmed
Joined: 09 Apr 2017
Last visit: 19 Dec 2022
Posts: 109
Own Kudos:
Given Kudos: 135
Status:Turning my handicaps into assets
Posts: 109
Kudos: 50
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,045
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 22 Apr 2026
Posts: 22,278
Own Kudos:
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,278
Kudos: 26,528
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Kudos
Add Kudos
Bookmarks
Bookmark this Post
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64
Bunuel
Discussed: https://gmatclub.com/forum/there-are-8- ... fl=similar
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
EMPOWERgmatRichC
Hi All,

Using the Combination Formula IS one way to approach these types of questions, but it's not the only way. Sometimes the easiest way to get to a solution on Test Day is to just draw a little picture and keep track of the possibilities....

Let's call the 8 teams: ABCD EFGH

We're told that each team plays each other team JUST ONCE.

Start with team A....
A plays BCD EFGH = 7 games total

Team B has ALREADY played team A, so those teams CANNOT play again...
B plays CD EFGH = 6 more games

Team C has ALREADY played teams A and B, so the following games are left...
C plays D EFGH = 5 more games

At this point, you should notice a pattern: the additional number of games played is reduced by 1 each time. So what we really have is:

7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 = 28 games played

Final Answer:
GMAT assassins aren't born, they're made,
Rich
EMPOWERgmatRichC
Thanks for the nice explanation.
In your explanation, zero (in the highlighted part) indicates that team H payed with team H. We should not count H vs H here, actually. Isn't it?
Thanks__
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,754
Own Kudos:
810,688
 [1]
Given Kudos: 105,823
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,754
Kudos: 810,688
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Asad
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64
Bunuel
Discussed: https://gmatclub.com/forum/there-are-8- ... fl=similar

That question is not the same:

There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,045
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,045
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Asad
EMPOWERgmatRichC
Hi All,

Using the Combination Formula IS one way to approach these types of questions, but it's not the only way. Sometimes the easiest way to get to a solution on Test Day is to just draw a little picture and keep track of the possibilities....

Let's call the 8 teams: ABCD EFGH

We're told that each team plays each other team JUST ONCE.

Start with team A....
A plays BCD EFGH = 7 games total

Team B has ALREADY played team A, so those teams CANNOT play again...
B plays CD EFGH = 6 more games

Team C has ALREADY played teams A and B, so the following games are left...
C plays D EFGH = 5 more games

At this point, you should notice a pattern: the additional number of games played is reduced by 1 each time. So what we really have is:

7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 = 28 games played

Final Answer:
GMAT assassins aren't born, they're made,
Rich
EMPOWERgmatRichC
Thanks for the nice explanation.
In your explanation, zero (in the highlighted part) indicates that team H payed with team H. We should not count H vs H here, actually. Isn't it?
Thanks__

Hi Asad,

The "0" at the end represents the additional number of games that Team H would have to play. Since Team H already played all of the other teams (and those games have been 'counted' already), there's nothing else to add to the total.

GMAT assassins aren't born, they're made,
Rich
User avatar
IloveMBA123
Joined: 22 Jul 2019
Last visit: 22 Mar 2024
Posts: 61
Own Kudos:
Given Kudos: 38
Posts: 61
Kudos: 12
Kudos
Add Kudos
Bookmarks
Bookmark this Post
There are 8 teams in a certain league and each team plays each of the other teams exactly once.

What does this mean? each team plays each of the other teams exactly once? what are they playing? one another's hand? hair? finger?
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,045
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,045
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
waihoe520
There are 8 teams in a certain league and each team plays each of the other teams exactly once.

What does this mean? each team plays each of the other teams exactly once? what are they playing? one another's hand? hair? finger?

Hi waihoe520,

The prompt leaves the exact nature of what's being 'played' as an unknown, but if it helps, then you might assume that the 8 teams are probably playing some type of sport (such as basketball or baseball), although that's not really relevant to the math involved. There will be some type of competition in which each team plays each other team ONCE.

If we call the 8 teams: A, B, C, D, E, F, G and H

Then we know that Team A plays B, C, D, E, F, G, and H.... which is 7 games total

Since Team B has ALREADY played Team A, those teams CANNOT play again... thus, Team B plays C, D, E, F, G and H = 6 more games

Team C has ALREADY played Team A and Team B, so it would play D through H = 5 more games

Etc.

GMAT assassins aren't born, they're made,
Rich
User avatar
SenseiA
Joined: 19 Apr 2020
Last visit: 22 Apr 2026
Posts: 7
Own Kudos:
3
 [2]
Given Kudos: 171
GMAT 1: 660 Q48 V32
GMAT 1: 660 Q48 V32
Posts: 7
Kudos: 3
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Quote:
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64

There's a formula for questions such as this, similar to the formula for calculating the number of handshakes: \(\frac{n(n-1)}{2}\)

\(\frac{8(8-1)}{2}\)= 28

C
User avatar
woohoo921
Joined: 04 Jun 2020
Last visit: 17 Mar 2023
Posts: 493
Own Kudos:
Given Kudos: 623
Posts: 493
Kudos: 149
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ScottTargetTestPrep
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64


We are given that there are 8 teams in a league and that each game is played by 2 teams. Note that each team does not play itself, and the order of pairing each team with its opponent doesn't matter. [For example, the pairing of (Team A vs. Team B) is identical to the pairing of (Team B vs. Team A).] The situation can therefore be solved by finding the number of combinations of 8 items taken 2 at a time, or 8C2, as follows:

8C2 = 8! / [2! x (8-2)!]

(8 x 7 x 6!) / (2! x 6!)

(8 x 7)/2!

(8 x 7)/ 2

4 x 7 = 28

Answer C

ScottTargetTestPrep
Thank you! If order did matter, would you do [8!/(8-2)!)]? I get a bit confused on the anagram versus formula approach. Thank you and Happy New Year :)
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 22 Apr 2026
Posts: 22,278
Own Kudos:
26,528
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,278
Kudos: 26,528
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
woohoo921
ScottTargetTestPrep
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64


We are given that there are 8 teams in a league and that each game is played by 2 teams. Note that each team does not play itself, and the order of pairing each team with its opponent doesn't matter. [For example, the pairing of (Team A vs. Team B) is identical to the pairing of (Team B vs. Team A).] The situation can therefore be solved by finding the number of combinations of 8 items taken 2 at a time, or 8C2, as follows:

8C2 = 8! / [2! x (8-2)!]

(8 x 7 x 6!) / (2! x 6!)

(8 x 7)/2!

(8 x 7)/ 2

4 x 7 = 28

Answer C

ScottTargetTestPrep
Thank you! If order did matter, would you do [8!/(8-2)!)]? I get a bit confused on the anagram versus formula approach. Thank you and Happy New Year :)

Response:

That is exactly what we would do. If the question were such that each team played each of the other teams twice (for instance, one of the games could be a home game and the other game could be an away game), then team A vs. team B would no longer be identical to team B vs. team A. Notice that in either case, the same two teams play the game but in different order; thus, the order now matters. That’s why this question would be solved using permutations instead of combinations and 8P2 is precisely the expression you wrote.
User avatar
akadiyan
User avatar
Retired Moderator
Joined: 31 May 2017
Last visit: 20 Jun 2025
Posts: 724
Own Kudos:
Given Kudos: 53
Concentration: Technology, Strategy
Products:
Posts: 724
Kudos: 706
Kudos
Add Kudos
Bookmarks
Bookmark this Post
We can use either the combination formula or we can use the formula that we use for Round Robin method.

Combination formula = \(\frac{{n!}}{{k!(n-k)!}} = \frac{{8!}}{{2!(8-2)!}} \)= 28

Round robin =\(\frac{{N(N-1)}}{2}=\frac{{8(8-1)}}{2}=\frac{56}{2}\) = 28

Ans C
User avatar
CrackverbalGMAT
User avatar
Major Poster
Joined: 03 Oct 2013
Last visit: 22 Apr 2026
Posts: 4,846
Own Kudos:
9,180
 [1]
Given Kudos: 226
Affiliations: CrackVerbal
Location: India
Expert
Expert reply
Posts: 4,846
Kudos: 9,180
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Solution:

The total number of games played is counted by selecting two teams of 8.

We "select" or "choose" as choosing teams A & B for a game is similar to choosing B & A.

The total number of games played= 8 C 2

= 8! /2!(8-2)!

= 8! / 2! (6!)

=56/2

=28 (option c)

Hope this helps :thumbsup:
Devmitra Sen(GMAT Quant Expert)
User avatar
100mitra
Joined: 29 Apr 2019
Last visit: 06 Jul 2022
Posts: 707
Own Kudos:
Given Kudos: 49
Status:Learning
Posts: 707
Kudos: 634
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Correct Option : C - 28

Method 1 : Counting : 7+6+5+4+3+2+1 = 28
Method 2 : Combination : 8C2 = [8!/(2!x6!)] = 28
Method 3 : Mean : (8x7)/2 = 28
avatar
frickthegmat
avatar
Current Student
Joined: 11 Aug 2021
Last visit: 03 Jun 2025
Posts: 15
Own Kudos:
Given Kudos: 10
Location: United States (IL)
Posts: 15
Kudos: 7
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64

The total # of games played would be equal to the # of different pairs possible from 8 teams, which is \(C^2_{8}=28\).

Answer: C.

P.S. Please read and follow: https://gmatclub.com/forum/rules-for-pos ... 33935.html Pay attention ot the points #3 and #8.
8 choose 2 is NOT 28. 8 choose 2 is 56. The answer here is 28 BECAUSE 8 choose 2 DIVIDED BY 2 is 28.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,754
Own Kudos:
Given Kudos: 105,823
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,754
Kudos: 810,688
Kudos
Add Kudos
Bookmarks
Bookmark this Post
frickthegmat
Bunuel
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64

The total # of games played would be equal to the # of different pairs possible from 8 teams, which is \(C^2_{8}=28\).

Answer: C.

P.S. Please read and follow: https://gmatclub.com/forum/rules-for-pos ... 33935.html Pay attention ot the points #3 and #8.
8 choose 2 is NOT 28. 8 choose 2 is 56. The answer here is 28 BECAUSE 8 choose 2 DIVIDED BY 2 is 28.

\(C^2_{8}=\frac{8!}{2!6!}=\frac{7*8}{2}=28\).
User avatar
Dinesh654
Joined: 08 Jun 2021
Last visit: 11 Aug 2024
Posts: 151
Own Kudos:
Given Kudos: 217
Status:In learning mode...
Location: India
GMAT 1: 600 Q46 V27
Products:
GMAT 1: 600 Q46 V27
Posts: 151
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
sarb
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?

A. 15
B. 16
C. 28
D. 56
E. 64

The total # of games played would be equal to the # of different pairs possible from 8 teams, which is \(C^2_{8}=28\).

Answer: C.

P.S. Please read and follow: https://gmatclub.com/forum/rules-for-pos ... 33935.html Pay attention ot the points #3 and #8.

Hi Bunuel
I got it wrong.
can you please explain why can't we do- 8C1*7C1= 56
first we select one team from 8 and then one from remaining 7. hence, 1 game can be played
why am I wrong?
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,045
 [2]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,045
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Dinesh654,

The prompt tells us that each Team plays each of the other times ONCE. In your calculation though, you have them playing TWICE. Here's why.

We can start by referring to the Teams as A, B, C, D, E, F, G and H.

When Team A plays Team B, we have 1 game - and we would end up with 7 total games involving Team A (one per opponent). We have to make sure that Team A does NOT play any of those other teams again.

If you next take Team B - and then choose Team A as an opponent - then you've created a 2nd game between them, which is not allowed. Thus, under these conditions, you cannot simply multiply 8c1 and 7c1 - since this would actually create TWO games for each pairing.

GMAT assassins aren't born, they're made,
Rich

Contact Rich at: [email protected]
User avatar
nova31
Joined: 11 Jun 2019
Last visit: 04 Jul 2024
Posts: 13
Own Kudos:
Given Kudos: 74
Location: India
Concentration: Technology, Strategy
GMAT 1: 730 Q49 V40
GPA: 3.4
WE:Engineering (Computer Software)
GMAT 1: 730 Q49 V40
Posts: 13
Kudos: 14
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I used this approach, sharing if it helps others:

1st team plays 7 matches.
2nd team also plays 7 matches but we have counted that in previous team's tally already, so 7-1 = 6 matches to be added.
Similarly, 3rd - 5, 4th - 4,....

7+6+5+....+1 = 7(7+1) / 2 = 28.
   1   2   3   
Moderators:
Math Expert
109754 posts
Tuck School Moderator
853 posts