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a, b, c and d are consecutive integers such that the product [#permalink]
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05 Nov 2012, 07:01
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\(a\), \(b\), \(c\) and \(d\) are consecutive integers such that the product \(abcd=5040\), what is the value of \(d\)? (1) \(d\) is prime (2) \(a>b>c>d\)
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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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Updated on: 05 Nov 2012, 09:09
rajathpanta wrote: a,b,c and d are consecutive integers such that the product abcd=5040, what is the value of d?
(1) d is prime (2) a>b>c>d Question says, abcd =5040 thus a,b,c and d could be 7,8,9 and 10 or 7, 8, 9, 10 because 7*8*9*10 = 5040 and also (7)*(8)*(9)*(10)=5040 Statement 1: d is prime. Clearly d is 7, as prime can not be negative. Sufficient Statement 2: a>b>c>d => d could be 7 or 10. Not sufficient. Hence ans A it is.
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Originally posted by Vips0000 on 05 Nov 2012, 09:08.
Last edited by Vips0000 on 05 Nov 2012, 09:09, edited 1 time in total.




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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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05 Nov 2012, 08:04
Factorize: 5040 = \(2^4X3^2X5X7\) =7x8x9x10 A: If d is a prime, only possible value is 7.  Sufficient. B: a>b>c>d => d = 7  Sufficient Am I missing something ?
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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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05 Nov 2012, 09:08
ConnectTheDots wrote: Factorize:
5040 = \(2^4X3^2X5X7\) =7x8x9x10
A: If d is a prime, only possible value is 7.  Sufficient. B: a>b>c>d => d = 7  Sufficient
Am I missing something ? yes, possibility of negative numbers
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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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05 Nov 2012, 09:38
Yes thats the mean little trick there. You will have to consider the negative numbers too.
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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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31 May 2015, 01:10
rajathpanta wrote: a, b, c and d are consecutive integers such that the product abcd=5040, what is the value of d?
(1) d is prime (2) a>b>c>d In that case, answer should be E because with stmt 1 again, d value is either 7 or 7.



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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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31 May 2015, 06:09



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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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01 Jun 2015, 10:27
Hi Bunuel, Does that mean the anwer is wrong. Bunuel wrote: sinhap07 wrote: rajathpanta wrote: a, b, c and d are consecutive integers such that the product abcd=5040, what is the value of d?
(1) d is prime (2) a>b>c>d In that case, answer should be E because with stmt 1 again, d value is either 7 or 7. d is a prime number, so it cannot be 7. Only positive integers can be primes (the smallest prime is 2).
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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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01 Jun 2015, 10:40



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The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink]
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21 Jul 2016, 05:03



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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink]
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21 Jul 2016, 06:56
Bunuel wrote: The product of consecutive integers a, b, c, and d is 5,040. What is the value of d?
(1) d is prime
(2) d < c < b < a Given product of consecutive integers a, b, c, and d is 5,040 then we get 7 * 8* 9* 10.. 1. d is prime => and only prime in this series is 7...Sufficient. 2. d < c < b < a then it has to be 7 < 8 < 9 < 10... we get d as 7...Sufficient. IMO D is the correct answer...Both choices are independently sufficient.



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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink]
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21 Jul 2016, 07:33
a*b*c*d=5040 also 5040=2^4*3^2*5*7 or, 5040=10*9*8*7
(1) d is prime
d=7 sufficient !!
(2) d < c < b < a
d=7 sufficient !!
D



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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink]
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21 Jul 2016, 08:50
Bunuel wrote: The product of consecutive integers a, b, c, and d is 5,040. What is the value of d?
(1) d is prime
(2) d < c < b < a Factors of 5,040= 10*9*8*7 (1) d is prime. Only prime number in factors is 7. Sufficient. (2) d < c < b < a d is the smallest number, i.e. 7. Sufficient. D is the answer
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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink]
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23 Jul 2016, 10:22
Bunuel wrote: The product of consecutive integers a, b, c, and d is 5,040. What is the value of d?
(1) d is prime
(2) d < c < b < a Consecutive integers will be 7,8,9,10 OR 7,8,9,10 Statement 1:d is primesufficientonly 7 is prime Statement 2:D is the smallest:Not sufficient:d can be 10 or 7 Answer A



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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink]
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23 Jul 2016, 18:29
Unless I missed something the same question was already present and indeed KS15 is right and the answer was A) Nice one. abcanddareconsecutiveintegerssuchthattheproduct141920.html



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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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14 Aug 2017, 04:43
rajathpanta wrote: \(a\), \(b\), \(c\) and \(d\) are consecutive integers such that the product \(abcd=5040\), what is the value of \(d\)?
(1) \(d\) is prime (2) \(a>b>c>d\) abcd = 5040, where a,b,c,d are consecutive integers. d = ? 1) d is prime 5040 = 7*8*9*10 => d = 7 Sufficient. 2) a > b > c > d d = 7 or d = 10 => a, b, c, d can also be negative consecutive integers. InSufficient. A is the answer.
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Re: a, b, c and d are consecutive integers such that the product [#permalink]
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26 Sep 2017, 23:16
rajathpanta wrote: \(a\), \(b\), \(c\) and \(d\) are consecutive integers such that the product \(abcd=5040\), what is the value of \(d\)?
(1) \(d\) is prime (2) \(a>b>c>d\) Tricky x (x+1)(x+2)(x+3) =5040  7<x<10 2^4 *7 *2 * 5  hidden in here is 7 * 8 *9 *10 Statement 1 A prime number cannot be negative suff Statement 2 Actually, because there are four numbers you could technically have 7 insuff A




Re: a, b, c and d are consecutive integers such that the product
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