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a, b, c and d are consecutive integers such that the product [#permalink ]

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05 Nov 2012, 06:01
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\(a\), \(b\), \(c\) and \(d\) are consecutive integers such that the product \(abcd=5040\), what is the value of \(d\)?

(1) \(d\) is prime

(2) \(a>b>c>d\)

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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05 Nov 2012, 07:04
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Factorize:

5040

= \(2^4X3^2X5X7\)

=7x8x9x10

A: If d is a prime, only possible value is 7. - Sufficient.

B: a>b>c>d => d = 7 - Sufficient

Am I missing something ?

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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05 Nov 2012, 08:08
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rajathpanta wrote:

a,b,c and d are consecutive integers such that the product abcd=5040, what is the value of d? (1) d is prime (2) a>b>c>d

Question says,

abcd =5040

thus

a,b,c and d could be 7,8,9 and 10 or -7, -8, -9, -10 because

7*8*9*10 = 5040

and also

(-7)*(-8)*(-9)*(-10)=5040

Statement 1: d is prime. Clearly d is 7, as prime can not be negative. Sufficient

Statement 2: a>b>c>d => d could be 7 or -10. Not sufficient.

Hence ans A it is.

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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05 Nov 2012, 08:08
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ConnectTheDots wrote:

Factorize: 5040 = \(2^4X3^2X5X7\) =7x8x9x10 A: If d is a prime, only possible value is 7. - Sufficient. B: a>b>c>d => d = 7 - Sufficient Am I missing something ?

yes, possibility of negative numbers

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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05 Nov 2012, 08:38
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Yes thats the mean little trick there. You will have to consider the negative numbers too.

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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31 May 2015, 00:10

rajathpanta wrote:

a, b, c and d are consecutive integers such that the product abcd=5040, what is the value of d? (1) d is prime (2) a>b>c>d

In that case, answer should be E because with stmt 1 again, d value is either 7 or -7.

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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31 May 2015, 05:09
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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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01 Jun 2015, 09:27

Hi Bunuel,

Does that mean the anwer is wrong.

Bunuel wrote:

sinhap07 wrote:

rajathpanta wrote:

a, b, c and d are consecutive integers such that the product abcd=5040, what is the value of d? (1) d is prime (2) a>b>c>d

In that case, answer should be E because with stmt 1 again, d value is either 7 or -7.

d is a prime number, so it cannot be -7. Only positive integers can be primes (the smallest prime is 2).

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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01 Jun 2015, 09:40
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The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink ]

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21 Jul 2016, 04:03
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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink ]

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21 Jul 2016, 05:56

Bunuel wrote:

The product of consecutive integers a, b, c, and d is 5,040. What is the value of d? (1) d is prime (2) d < c < b < a

Given product of consecutive integers a, b, c, and d is 5,040 then we get 7 * 8* 9* 10..

1. d is prime => and only prime in this series is 7...Sufficient.

2. d < c < b < a then it has to be 7 < 8 < 9 < 10... we get d as 7...Sufficient.

IMO D is the correct answer...Both choices are independently sufficient.

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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink ]

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21 Jul 2016, 06:33

a*b*c*d=5040 also 5040=2^4*3^2*5*7 or, 5040=10*9*8*7 (1) d is prime d=7 ---sufficient !! (2) d < c < b < a d=7 ---sufficient !! D

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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink ]

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21 Jul 2016, 07:50

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Bunuel wrote:

The product of consecutive integers a, b, c, and d is 5,040. What is the value of d? (1) d is prime (2) d < c < b < a

Factors of 5,040= 10*9*8*7

(1) d is prime. Only prime number in factors is 7.

Sufficient.

(2) d < c < b < a

d is the smallest number, i.e. 7. Sufficient.

D is the answer

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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink ]

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23 Jul 2016, 09:22

Bunuel wrote:

The product of consecutive integers a, b, c, and d is 5,040. What is the value of d? (1) d is prime (2) d < c < b < a

Consecutive integers will be 7,8,9,10 OR -7,-8,-9,-10

Statement 1:d is prime-sufficient-only 7 is prime

Statement 2:D is the smallest:Not sufficient:d can be -10 or 7

Answer A

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Re: The product of consecutive integers a, b, c, and d is 5,040. What is [#permalink ]

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23 Jul 2016, 17:29

Unless I missed something the same question was already present and indeed KS15 is right and the answer was A)

Nice one.

a-b-c-and-d-are-consecutive-integers-such-that-the-product-141920.html
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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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14 Aug 2017, 03:43

rajathpanta wrote:

\(a\), \(b\), \(c\) and \(d\) are consecutive integers such that the product \(abcd=5040\), what is the value of \(d\)? (1) \(d\) is prime (2) \(a>b>c>d\)

abcd = 5040, where a,b,c,d are consecutive integers.

d = ?

1) d is prime

5040 = 7*8*9*10

=> d = 7

Sufficient.

2) a > b > c > d

d = 7 or d = -10

=> a, b, c, d can also be negative consecutive integers.

InSufficient.

A is the answer.

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Re: a, b, c and d are consecutive integers such that the product [#permalink ]

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26 Sep 2017, 22:16

rajathpanta wrote:

\(a\), \(b\), \(c\) and \(d\) are consecutive integers such that the product \(abcd=5040\), what is the value of \(d\)? (1) \(d\) is prime (2) \(a>b>c>d\)

Tricky

x (x+1)(x+2)(x+3) =5040 --- 7<x<10

2^4 *7 *2 * 5 --- hidden in here is 7 * 8 *9 *10

Statement 1

A prime number cannot be negative

suff

Statement 2

Actually, because there are four numbers you could technically have -7

insuff

A

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Re: a, b, c and d are consecutive integers such that the product
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26 Sep 2017, 22:16