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28 May 2017, 01:50
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In the triangle above is RP > PQ ?
(1) y = 180 – x
(2) y = z = 60
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2017-05-28_1248.png [ 6.98 KiB | Viewed 2595 times ]
28 May 2017, 02:22
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From the triangle
y+z+180-x = 180
y+z = x
1. y = 180 – x
Substituting in the equation, y+z = x
180 + z = 2x
If angle x is obtuse(specifically equal than 120), there is a possibility of this equation holding true.
But there can be a lot of combinations for angle z and y for which this equation will hold good.
Therefore, we cannot clearly predict which side will be longer.
Hence, insufficient.
2. y = z = 60
When this happens, the triangle will become an equilateral triangle where all sides are equal.
This alone is sufficient.(Option B)
y+z+180-x = 180
y+z = x
1. y = 180 – x
Substituting in the equation, y+z = x
180 + z = 2x
If angle x is obtuse(specifically equal than 120), there is a possibility of this equation holding true.
But there can be a lot of combinations for angle z and y for which this equation will hold good.
Therefore, we cannot clearly predict which side will be longer.
Hence, insufficient.
2. y = z = 60
When this happens, the triangle will become an equilateral triangle where all sides are equal.
This alone is sufficient.(Option B)
23 Jan 2018, 01:27
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I have a doubt here:
cant it be for the first statement : (1) y = 180 – x is given => x+y= 180 linear pair => the traingle is isosceles with pq = pr => RP< PQ ?
and hence D as ans?
somebody please clarify. @bunnuel
cant it be for the first statement : (1) y = 180 – x is given => x+y= 180 linear pair => the traingle is isosceles with pq = pr => RP< PQ ?
and hence D as ans?
somebody please clarify. @bunnuel
