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13 May 2016, 05:00
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x and y are integers. x + y < 11 , and x > 6. What is the smallest possible value of x - y ?
A. 1
B. 2
C. 4
D. -2
E. -4
A. 1
B. 2
C. 4
D. -2
E. -4
13 May 2016, 13:50
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Constraints: X>6, x,y are integers (no fractions) and x+y<11 (can be positive or negative)
Test Case 1: X and Y are positive:
X(>6) Y(positive integer) X+Y<11 X-Y
7 3 10 4
8 2 10 6
9 1 10 8
10 0 0 10
Least difference in the above is 4
Test Case 2 : X is positive Y is negative:
X(>6) Y(positive integer) X+Y<11 X-Y
7 -8 -1 15
8 -7 1 15
9 -6 3 15
10 -4 6 14
Least Difference X-Y as you can is far higher when Y is negative. Hence test case 2 is rules out , going by test case 1 and other constraints defined in the problem only answer is Least difference in the above is Choice C- 4
Test Case 1: X and Y are positive:
X(>6) Y(positive integer) X+Y<11 X-Y
7 3 10 4
8 2 10 6
9 1 10 8
10 0 0 10
Least difference in the above is 4
Test Case 2 : X is positive Y is negative:
X(>6) Y(positive integer) X+Y<11 X-Y
7 -8 -1 15
8 -7 1 15
9 -6 3 15
10 -4 6 14
Least Difference X-Y as you can is far higher when Y is negative. Hence test case 2 is rules out , going by test case 1 and other constraints defined in the problem only answer is Least difference in the above is Choice C- 4
MrWriter
Joined: 11 Mar 2016
Last visit: 07 Jul 2024
Posts: 20
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Location: India
Concentration: Statistics, Finance
Schools: Kenan-Flagler '22 (A$) Jones '22 (A$) Olin '22 (WA) Mendoza '22 (A$) Foster '22 (D) Kelley '22 (D)
GMAT 1: 730 Q50 V38
Schools: Kenan-Flagler '22 (A$) Jones '22 (A$) Olin '22 (WA) Mendoza '22 (A$) Foster '22 (D) Kelley '22 (D)
GMAT 1: 730 Q50 V38
Posts: 20
Kudos:
9
06 Jun 2016, 21:46
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Bunuel
x and y are integers. x + y < 11 , and x > 6. What is the smallest possible value of x - y ?
A. 1
B. 2
C. 4
D. -2
E. -4
A. 1
B. 2
C. 4
D. -2
E. -4
Because x & y are integers, the two equations can be simply written as :
x+y<= 10 --- eq. 1
x>= 7 ---- eq. 2
For smallest value of x-y, x has to be the smallest whereas y has to be the largest.
From the above eq. 2, smallest value of x = 7
Plugging it in eq. 1: 7+y<=10, or y<=3
Therefore, largest value of y=3 & smallest values of x=7
x-y = 7 - 3 = 4
Answer is C
