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# Eddy and Freddy start simultaneously from city A and they travel to

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Math Expert
Joined: 02 Sep 2009
Posts: 50585
Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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09 Dec 2015, 07:12
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3
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Difficulty:

25% (medium)

Question Stats:

78% (02:09) correct 22% (02:40) wrong based on 167 sessions

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Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

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Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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09 Dec 2015, 07:26
Distance traveled by Eddy = 600 km
Time taken by Eddy = 3 hours
Average speed of Eddy = 600/3 = 200 km/hour

Distance traveled by Freddy = 300 km
Time taken by Freddy = 4 hours
Average speed of Freddy = 300/4 = 75 km/hour

Ratio of average speed of Eddy to Freddy = 200/75 = 8/3
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Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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09 Dec 2015, 07:50
Bunuel wrote:
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

1 approach. If Eddy had traveled 300 km (two times less than Freddy), he would have come to destination in 1.5 hours. Eddy needs 3/8 (or 1.5/4) time less to get to his point than Freddy to Freddy's point. Therefore, Eddy's rate of speed is 8/3 greater than that of Freddy because time and rate are reciprocals.

2 approach. The speed of Eddy is 600km/3hours = 200 km/h. The speed of Freddy is 400km/1.5hours = 75 km/h. Therefore, the ratio of Eddy: Freddy average speed of travel is 200/75 = 8/3
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Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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06 Jun 2017, 18:57
Speed of Eddy = 600/3 = 200 km/h
Speed of Freddy = 300/4 = 75 km/h

Required ratio = 200/75 = 8/3. Hence A answer
Intern
Joined: 30 Jul 2016
Posts: 6
Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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25 Jun 2017, 06:11
Bunuel wrote:
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

I consider the total distance 900 km for both. and get to 4/3. i cant get why the proposed solutions considering Eddy's distance 600 and the other 300. can you explain? ?thanks in advance
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Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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25 Jun 2017, 06:32
Bunuel wrote:
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

Eddy traveled to City B from City A.

Distance between City A and City B $$= 600$$ kms

Time taken by Eddy to travel from city A to B $$= 3$$ hours

Speed of Eddy $$= \frac{600}{3} = 200$$ kms/hr

Freddy traveled to City C from City A.

Distance between City A and City C $$= 300$$ kms

Time taken by Freddy to travel from city A to C $$= 4$$ hours

Speed of Freddy $$= \frac{300}{4} = 75$$ kms/hr

Required ratio = Average speed of Eddy / Average speed of Freddy $$= \frac{200}{75} = \frac{8}{3}$$ . Answer (A) ...
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Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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25 Jun 2017, 06:47

600/3 : 300/4
200 : 75 = 8:3
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Joined: 22 May 2016
Posts: 2092
Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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25 Jun 2017, 12:30
1
Yoohanna wrote:
Bunuel wrote:
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

I consider the total distance 900 km for both. and get to 4/3. i cant get why the proposed solutions considering Eddy's distance 600 and the other 300. can you explain? ?thanks in advance

I agree with you. I think the question is phrased ambiguously.

"Respectively" here could mean:

1) both Eddie and Freddie traveled to city B, then they both "doubled back" to city C (which is what I assumed, especially given test writers' penchant for subtle details); or

2) only Eddie went to city B and only Freddie went to city C.

"Respectively" typically should come at or near the end of a sentence, as long as one-to-one correspondence to its two referents is direct and apparent. "Respectively" modifies "travel," but the latter involves both the travelers and their destinations.

Yoohanna, the best I can say is that when you see the word "respectively," and it is not clear what "respectively" refers to, AND your answer doesn't show up in the choices, look for other things in the sentence to which "respectively" might refer.

The ambiguity is frustrating in an otherwise good question. YMMV
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Posts: 606
Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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05 Sep 2018, 07:26
1
Bunuel wrote:
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

Dear Moderator,
Found this Distance , rate and speed problem in the combination section, hope you will do the needful. Thank you.
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- Stne

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Joined: 02 Sep 2009
Posts: 50585
Re: Eddy and Freddy start simultaneously from city A and they travel to  [#permalink]

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05 Sep 2018, 07:35
stne wrote:
Bunuel wrote:
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)

A. 8/3
B. 3/8
C. 8/5
D. 5/8
E. 5/3

Dear Moderator,
Found this Distance , rate and speed problem in the combination section, hope you will do the needful. Thank you.

_______________
Edited. Thank you.
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Re: Eddy and Freddy start simultaneously from city A and they travel to &nbs [#permalink] 05 Sep 2018, 07:35
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