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Awli
Three employees, A, B and C, clean a certain conference room each day. Working together, A and B can clean the conference room in 3 hours, whereas A and C together can do it in 2 and 1/2 hours. Can A, B and C working together clean the conference room in less than 2 hours?

1) B cleans faster than A.
2) Working alone, C can clean the conference room in less tahn 5 hours.

hi Awli,
ans D..
1) statement one tells us B>A so both A and B do it in 3 hrs.. lets take the worst scenario that B is just above A or almost same so A's speed = B's speed = 6 hrs..
so C's speed = 2/5-1/6=7/30... so A,B and C can do it in 1/6+1/6+7/30=17/30.. so time taken =30/17=1 13/17 days<2 days... sufficient
2) let the worst scenario C takes 5 hrs so total time=1/3+1/5=8/15 or 15/8 days<2 days .. sufficient
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Hi sytabish,

Most Test Takers approach 'Work Formula' questions by converting data into a 'fraction of work done per hour' format or using the Work Formula (if it's two entities working on a job). Since data can be converted from one format to many different formats (fractions to decimals to percents to ratios, etc.), there is nothing wrong with what you did. It's a rather clever way to look at the data and just as valid as any other approach.

GMAT assassins aren't born, they're made,
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EMPOWERgmatRichC
Hi sytabish,

Most Test Takers approach 'Work Formula' questions by converting data into a 'fraction of work done per hour' format or using the Work Formula (if it's two entities working on a job). Since data can be converted from one format to many different formats (fractions to decimals to percents to ratios, etc.), there is nothing wrong with what you did. It's a rather clever way to look at the data and just as valid as any other approach.

GMAT assassins aren't born, they're made,
Rich

Thanks for the confirmation EMPOWERgmatRichC !
I have been trying to use the percentage approach wherever I can for Work rate problems.
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Three employees, A, B and C, clean a certain conference room each day. Working together, A and B can clean the conference room in 3 hours, whereas A and C together can do it in 2 and 1/2 hours. Can A, B and C working together clean the conference room in less than 2 hours?

we have two equations :1) \(\frac{1}{A}+\frac{1}{B}=\frac{1}{3}\)

2) \(\frac{1}{A}+\frac{1}{C}=\frac{1}{2.5}\)

and we are asked , is \(\frac{1}{A}+\frac{1}{B}+\frac{1}{C}>\frac{1}{2}\) ?

substitute equation 1.------->\(\frac{1}{3}+\frac{1}{C}>\frac{1}{2}\)--->6+2C>3C---->is 6>C ?.

Substitute equation 2.----->\(\frac{1}{2.5}+\frac{1}{B}>\frac{1}{2}\)--->5+2B>2.5B---> is 10>B ?.

check either of the above two conditions.

Statement 1): B cleans faster than A----> B<A , and from the equation 1(\(\frac{1}{A}+\frac{1}{B}=\frac{1}{3}\)) if B cleans as fast as A then A=B=6 , But we are given that B<A then B must be less than 6 ----> B<6
Then condition, is 10>B ----> ALWAYS YES, because 10>6>B

Statement 1 SUFFICIENT

Statement 2): Working alone, C can clean the conference room in less tahn 5 hours.---> C<5
condition , is 6>C--->ALWAYS YES, because 6>5>C

Statement 2 SUFFIECIENT

ANS---> D

please correct me if i am wrong

Thanks,
Adla.
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Thank you very much to all of you. I've found very useful all the approaches.
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Awli
Three employees, A, B and C, clean a certain conference room each day. Working together, A and B can clean the conference room in 3 hours, whereas A and C together can do it in 2 and 1/2 hours. Can A, B and C working together clean the conference room in less than 2 hours?

1) B cleans faster than A.
2) Working alone, C can clean the conference room in less tahn 5 hours.

hi Awli,
ans D..
1) statement one tells us B>A so both A and B do it in 3 hrs.. lets take the worst scenario that B is just above A or almost same so A's speed = B's speed = 6 hrs..
so C's speed = 2/5-1/6=7/30... so A,B and C can do it in 1/6+1/6+7/30=17/30.. so time taken =30/17=1 13/17 days<2 days... sufficient
2) let the worst scenario C takes 5 hrs so total time=1/3+1/5=8/15 or 15/8 days<2 days .. sufficient



This is the best way to solve DS problems :)
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Awli
Three employees, A, B and C, clean a certain conference room each day. Working together, A and B can clean the conference room in 3 hours, whereas A and C together can do it in 2 and 1/2 hours. Can A, B and C working together clean the conference room in less than 2 hours?

1) B cleans faster than A.
2) Working alone, C can clean the conference room in less than 5 hours.

A + B , Time = 3 hrs, so per hr work = 33.33% of total work.
A + C , Time = 2.5 hrs, so per hr work = 40% of total work.
Need to know, whether A+B+C can complete in less than 2 hrs. or A+B+C can do more than 50% work per hr.

1) Rate of B faster than A.
Therefore, B will do work which is greater than 1/2(33.33)% , i.e. greater than 16.5 %
Now add B's effort in A+C's effort(40%). We get A+B+C's effort > 50 %
Suff.

2) C can do more than 20% of the job per hr.
Now add C's effort with A+B( 33.33%), i.e. A+B+C can do more than 50% of the work per hr.
Suff.

Hence (D)

Please lemme know if there's anything wrong in my logic.

Thanks!!

Hey,
From where do you get that 1/2(33.33)% ?
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Prompt analysis
Let the rate of work done per hour for A, B, C be a,b,c respectively.According to the question:
(a+b)*3 = (b+c)*2.5 = (a+b+c)t

Superset
The answer could be YES or NO.

Translation
To find the value of t we need:
1# exact value of a, b, c.
2# some equations to find the value of t
3# any other information that will help to infer the value or range of t.

Statement analysis
St 1: b>a. lets take the worst scenario that B is just above A or almost same so A's speed = B's speed = 6 hrs..
so C's speed = 2/5-1/6=7/30... so A,B and C can do it in 1/6+1/6+7/30=17/30.. so time taken =30/17=1 13/17 days<2 days... sufficient
St 2: let the worst scenario C takes 5 hrs so total time=1/3+1/5=8/15 or 15/8 days<2 days .. sufficient
Option D
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Let Rate of A = A, Rate of B = B, Rate of C = C

Given : A + B = 1/3 (since it takes 3 hours to clean together)
A + C = 2/5 (since it takes 5/2 hours to clean together)
Question: A + B + C > 1/2 ? (does it take less than 2 hours to clean together)
1/3 + C > 1/2 ?
C > 1/6 ? or does C take less than 6 hours to clean alone?

Statement 1: B cleans faster than A.
If B were to clean at same rate as A (worst case), A + B = 1/3 => A + A = 1/3 => A = 1/6
now we have A + C = 2/5 => C = 2/5 - 1/6 (worst case) = 7/30 (greater than 1/6)
but since B cleans faster than A, A < 1/6, so above eqn C = 2/5 - (<1/6) > (7/30) (again greater than 1/6)
=> Sufficient

Statement 2: Working alone, C can clean the conference room in less than 5 hours => directly answers our question -> suff

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Answer (D)
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