|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
BillyZ
Current Student
Joined: 14 Nov 2016
Last visit: 06 Jun 2026
Posts: 1,134
Given Kudos: 926
Location: Malaysia
Concentration: General Management, Strategy
Schools: Sloan '23 (D) Tuck '23 (D) Darden '23 (D) Ross '23 (D) Kellogg '23 (D) Wharton '23 (D) Booth '23 (D) Fuqua '24 (A) Harvard '24 (D) Stanford '24 (D)
GMAT 1: 750 Q51 V40 (Online)
GPA: 3.53
Products:
Schools: Sloan '23 (D) Tuck '23 (D) Darden '23 (D) Ross '23 (D) Kellogg '23 (D) Wharton '23 (D) Booth '23 (D) Fuqua '24 (A) Harvard '24 (D) Stanford '24 (D)
GMAT 1: 750 Q51 V40 (Online)
Posts: 1,134
27 Mar 2017, 01:44
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:59) correct
36%
(02:26)
wrong
based on 228
sessions
History
Date
Time
Result
Not Attempted Yet
The volume of a rectangular box x inches wide, y inches long, and z inches high is 108 \(in^3\). If \(x ≤ y ≤ z\), what is x + yz?
(1) The area of the largest face of the box is 36 \(in^2\).
(2) The longest edge of the box is 9 inches.
(1) The area of the largest face of the box is 36 \(in^2\).
(2) The longest edge of the box is 9 inches.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
27 Mar 2017, 01:55
Kudos
Bookmarks
The volume of a rectangular box x inches wide, y inches long, and z inches high is 108 \(in^3\). If \(x ≤ y ≤ z\), what is x + yz?
The volume = (width)*(length)*(height) = xyz = 108.
(1) The area of the largest face of the box is 36 \(in^2\) --> since \(x ≤ y ≤ z\), the area of the largest face is yz, thus given that yz = 36. Substitute in the volume formula: x*yz = 36x = 108 --> x = 3. Therefore, x + yz = 3 + 36 = 39. Sufficient.
(2) The longest edge of the box is 9 inches --> z = 9 --> xy = 12. Multiple values are possible: for example, x = 2 and y = 6, OR x = 3 and y = 4. Not sufficient.
Answer: A.
Hope it's clear.
The volume = (width)*(length)*(height) = xyz = 108.
(1) The area of the largest face of the box is 36 \(in^2\) --> since \(x ≤ y ≤ z\), the area of the largest face is yz, thus given that yz = 36. Substitute in the volume formula: x*yz = 36x = 108 --> x = 3. Therefore, x + yz = 3 + 36 = 39. Sufficient.
(2) The longest edge of the box is 9 inches --> z = 9 --> xy = 12. Multiple values are possible: for example, x = 2 and y = 6, OR x = 3 and y = 4. Not sufficient.
Answer: A.
Hope it's clear.
TheUltimateWinner
Joined: 23 Feb 2015
Last visit: 29 Aug 2026
Posts: 2,464
Own Kudos:
Given Kudos: 1,990
Concentration: Finance, Technology
Schools: Harvard '24 Judge '23 LBS '24 McCombs '24 Mendoza Tepper '24 Ross '24 Cox Marshall '24 Fisher Kelley '24 Jones McDonough '24 Owen '24 Terry BU Simon '24 Katz GWU Mason Babson Gabelli Foster '24 Goizueta '24 Scheller Stern '23 CBS '23 Booth '23 Haas '25 Wharton '25 Stanford '26 Johnson'23 Fuqua '23 Kellogg '23 Kenan-Flagler'23 INSEAD Aug 22 intake Olin '23 Said '23 Sloan '23 Carey Arizona "22 Yale '23 UC Davis Madison '23 Anderson '23 Carroll Carlson '23 Darden '23
Schools: Harvard '24 Judge '23 LBS '24 McCombs '24 Mendoza Tepper '24 Ross '24 Cox Marshall '24 Fisher Kelley '24 Jones McDonough '24 Owen '24 Terry BU Simon '24 Katz GWU Mason Babson Gabelli Foster '24 Goizueta '24 Scheller Stern '23 CBS '23 Booth '23 Haas '25 Wharton '25 Stanford '26 Johnson'23 Fuqua '23 Kellogg '23 Kenan-Flagler'23 INSEAD Aug 22 intake Olin '23 Said '23 Sloan '23 Carey Arizona "22 Yale '23 UC Davis Madison '23 Anderson '23 Carroll Carlson '23 Darden '23
Posts: 2,464
Kudos:
2,510
27 Mar 2017, 02:09
Kudos
Bookmarks
ziyuen
Statement 1 :
yz=36
So, x=3
So, after putting the value of x and yz, we get a definite result, so SUFFICIENT.
Statement 2:
here, z=9
we know that xyz=108
So, xy=12
for different values of xy, it gives 12. So, the value of x+yz vary time to time.=>Insufficient.
So, The correct choice is .
Thank you...
