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In circle O above, if POQ is a right triangle and radius OP = 2, what

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In circle O above, if POQ is a right triangle and radius OP = 2, what  [#permalink]

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New post 15 Mar 2018, 23:44
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In circle O above, if POQ is a right triangle and radius OP = 2, what is the area of the shaded region?


(A) \(4\pi – 2\)

(B) \(4\pi — 4\)

(C) \(2\pi – 2\)

(D) \(2\pi — 4\)

(E) \(\pi - 2\)


Attachment:
2018-03-16_1011.png
2018-03-16_1011.png [ 9.71 KiB | Viewed 540 times ]

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Re: In circle O above, if POQ is a right triangle and radius OP = 2, what  [#permalink]

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New post 15 Mar 2018, 23:44
Bunuel wrote:
Image
In circle O above, if POQ is a right triangle and radius OP = 2, what is the area of the shaded region?


(A) \(4\pi – 2\)

(B) \(4\pi — 4\)

(C) \(2\pi – 2\)

(D) \(2\pi — 4\)

(E) \(\pi - 2\)


Attachment:
2018-03-16_1011.png


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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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In circle O above, if POQ is a right triangle and radius OP = 2, what  [#permalink]

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New post 16 Mar 2018, 01:01
Bunuel wrote:
Image
In circle O above, if POQ is a right triangle and radius OP = 2, what is the area of the shaded region?


(A) \(4\pi – 2\)

(B) \(4\pi — 4\)

(C) \(2\pi – 2\)

(D) \(2\pi — 4\)

(E) \(\pi - 2\)


Attachment:
2018-03-16_1011.png


Area of shaded region = Area of Quarter Circle - Area of triangle POQ

Area of shaded region = (1/4)π2^2 - (1/2)*2*2 = π-2

Answer: option E
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In circle O above, if POQ is a right triangle and radius OP = 2, what  [#permalink]

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New post 16 Mar 2018, 07:56
Bunuel wrote:
Image
In circle O above, if POQ is a right triangle and radius OP = 2, what is the area of the shaded region?


(A) \(4\pi – 2\)

(B) \(4\pi — 4\)

(C) \(2\pi – 2\)

(D) \(2\pi — 4\)

(E) \(\pi - 2\)

Area of shaded region = (Sector area) - (Triangle Area)

• Sector area as fraction of the circle's area

The key to these kinds of problems often is:
"The sector is what fraction of the circle?"

Use the sector's central angle (given, = 90°) to find that fraction

\(\frac{Part}{Whole}=\frac{SectorAngle}{360°}=\frac{90}{360}=\frac{1}{4}=\frac{SectorArea}{CircleArea}\)

Area of sector = \(\frac{1}{4}\) area of circle

• Area of circle and area of sector

Circle area, r = 2: \(πr^2 = 4π\)
Sector area: \(\frac{4π}{4}\)= \(π\)

• Area of triangle

Area of triangle with radii as sides (s = b and h):
\(\frac{s*s}{2} = \frac{4}{2}\) = \(2\)

• Area of shaded region
= (Area of sector) - (Area of triangle)

Area of shaded region = \(π - 2\)

Answer E
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In circle O above, if POQ is a right triangle and radius OP = 2, what &nbs [#permalink] 16 Mar 2018, 07:56
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