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In the figure above, arc SBT is one quarter of a circle with center R

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In the figure above, arc SBT is one quarter of a circle with center R [#permalink]

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New post 23 Nov 2017, 01:22
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In the figure above, arc SBT is one quarter of a circle with center R and radius 6. If the length plus the width of rectangle ABCR is 8, then the perimeter of the shaded region is

(A) 8 + 3π
(B) 10 + 3π
(C) 14 + 3π
(D) 1 + 6π
(E) 12 + 6π

Attachment:
2017-11-23_1215_001.png
2017-11-23_1215_001.png [ 13.95 KiB | Viewed 1832 times ]

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Re: In the figure above, arc SBT is one quarter of a circle with center R [#permalink]

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New post 23 Nov 2017, 17:41
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Bunuel wrote:
Image
In the figure above, arc SBT is one quarter of a circle with center R and radius 6. If the length plus the width of rectangle ABCR is 8, then the perimeter of the shaded region is

(A) 8 + 3π
(B) 10 + 3π
(C) 14 + 3π
(D) 1 + 6π
(E) 12 + 6π

Attachment:
2017-11-23_1215_001.png


It should be B.

Length of Arc is quarter of circumference of circle so

\(Arc = 2πr/4 = 2π6/4 = 3π\)

Rectangle ABCR is sum of two triangles \(\triangle ABC\) and \(\triangle ARC\) where diagonals \(RB\) and \(AC\) are equal to radius of the Circle. If it were a regular quarter circle, perimeter would have been 3π + 2*radius. However, It appears the shaded region just subtracts length and breadth of the rectangle (given as 8) from the two radius and bypasses it with the diagonal of the rectangle instead.

\(3π + 12 - 8 + 6 = 10 + 3π\)
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Re: In the figure above, arc SBT is one quarter of a circle with center R [#permalink]

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New post 23 Nov 2017, 23:41
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Bunuel wrote:
Image
In the figure above, arc SBT is one quarter of a circle with center R and radius 6. If the length plus the width of rectangle ABCR is 8, then the perimeter of the shaded region is

(A) 8 + 3π
(B) 10 + 3π
(C) 14 + 3π
(D) 1 + 6π
(E) 12 + 6π

Attachment:
2017-11-23_1215_001.png



Perimeter of shaded region = Perimeter of quarter circle SRT - (Length + Width of rectangle) + Diagonal of rectangle (AC)

The diagonal of the rectangle is same as the radius of the circle i.e. 6.

Perimeter of quarter circle SRT = 6 + 6 + (1/4)*2π*6 = 12 + 3π

Perimeter of shaded region = 12 + 3π - 8 + 6 = 10 + 3π

Answer (B)
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Re: In the figure above, arc SBT is one quarter of a circle with center R   [#permalink] 23 Nov 2017, 23:41
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