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# If p + q = r, what is the average of p, q, and r ?

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If p + q = r, what is the average of p, q, and r ?  [#permalink]

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20 May 2017, 06:02
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5% (low)

Question Stats:

94% (00:19) correct 6% (02:53) wrong based on 43 sessions

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If p + q = r, what is the average of p, q, and r ?

(A) r/3
(B) (p + q)/3
(C) 2r/3
(D) r/2
(E) (p + q)/2

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Re: If p + q = r, what is the average of p, q, and r ?  [#permalink]

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20 May 2017, 06:08
Bunuel wrote:
If p + q = r, what is the average of p, q, and r ?

(A) r/3
(B) (p + q)/3
(C) 2r/3
(D) r/2
(E) (p + q)/2

Average = (p+q+r)/3 =(r+r)/3
=2r/3

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Re: If p + q = r, what is the average of p, q, and r ?  [#permalink]

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20 May 2017, 06:08
Bunuel wrote:
If p + q = r, what is the average of p, q, and r ?

(A) r/3
(B) (p + q)/3
(C) 2r/3
(D) r/2
(E) (p + q)/2

$$p+q=r$$, $$p=r-q$$

$$Average = \frac{p+q+r}{3} = \frac{r-q+q+r}{3}=\frac{2r}{3}$$

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21 May 2017, 01:48
Average = Sum of terms divided by number of terms.

Average of p, q, r is
(p+q+r)/3

But, given, p+q=r

Therefore average of p, q, r is
(r+r)/3 = 2r/3

C.

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If p + q = r, what is the average of p, q, and r ?  [#permalink]

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21 May 2017, 05:21
If p + q = r, what is the average of p, q, and r ?

Average = Sum / Number of units
Average = $$\frac{p + q + r}{3}$$
Given; p + q = r
Therefore;
Average = $$\frac{r + r}{3}$$ = $$\frac{2r}{3}$$

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If p + q = r, what is the average of p, q, and r ? &nbs [#permalink] 21 May 2017, 05:21
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