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On the number line above, p, q, r, s, and t are five consec

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On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 07 Dec 2012, 07:30
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On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24
(2) The average (arithmetic mean) of q and r is 11.
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 07 Dec 2012, 07:37
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On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

{p, q, r, s, t} is an evenly spaced set thus its mean = median = middle term = r.

(1) q + s =24. Since q, r and s are consecutive even integers, then q=r-2 and s=r+2 --> (r-2)+(r+2)=24 --> r=12. Sufficient.

(2) The average (arithmetic mean) of q and r is 11. (r-2)+r=2*11 --> r=12. Sufficient.

Answer: D.
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 10 Dec 2012, 07:26
which is the level of the question? 500? tks a lot :)
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 10 Dec 2012, 07:42
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 11 Dec 2012, 03:54
Walkabout wrote:
Attachment:
Number line.png
On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24
(2) The average (arithmetic mean) of q and r is 11.


Ans. : Let p=x, q=x+2, r=x+4 , s=x+6, t=x+8 to find the mean we need to find x.
From statement 1 , we get 2x+8=24
From statement 2 we get x+3=11
Therefore the answer is (D).
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 16 Dec 2012, 12:38
My understanding of consecutive integers, is that they are separated by only 1, i.e. 3, 4, 5, 6, 7, 8

I was able to find the first statement sufficient, but not the second, mainly because the answer uses the formula p + (p+2) +....

Why is 2 being added to P?
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 16 Dec 2012, 22:41
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kelleygrad05 wrote:
My understanding of consecutive integers, is that they are separated by only 1, i.e. 3, 4, 5, 6, 7, 8

I was able to find the first statement sufficient, but not the second, mainly because the answer uses the formula p + (p+2) +....

Why is 2 being added to P?


We are not told that p, q, r, s, and t are consecutive integers. We are given that p, q, r, s, and t are five consecutive EVEN integers. For example 2, 4, 6, 8, 10.
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 11 Jan 2014, 09:17
They are basically giving us some equation in disguise.

1. q+s=24 but for a fact set we know that the leap between q and s is 4 and this translates into an equation that subtracted gives us the value of q from which we can calculate the average.
2. q+r=22 same old story, the leap between q and r this time is 2 units. r-q=2 subtract it from the given equation and you are done you got one value, the remaining values follow logically.

D.
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 24 Feb 2015, 21:38
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Hi All,

This DS question is full of Number Properties and the math involved is fairly straight-forward. However, if you don't see the "elegant" approach to answer this question, then you can still use "brute force" and some basic Arithmetic to get the correct answer.

We're given a number line with 5 variables on it. We're told that the variables represent 5 CONSECUTIVE EVEN INTEGERS. That's a very specific set of "restrictions", so you can use them to your advantage if you have to "play around" with this question. We're asked for the AVERAGE of the 5 integers. Since we know that they're consecutive evens, if we can figure out ANY of them, then we can figure out the others AND answer the question.

Fact 1: Q + S = 24

Looking at the drawing, we know that Q, R and S are 3 CONSECUTIVE EVEN INTEGERS, so even if we don't know how to do the Algebra here, we can still run some TESTs....

IF Q, R and S are....
2, 4 and 6, then Q+S = 8. That's too small though (it's supposed to be 24)

IF Q, R and S are a bit bigger, say....
8, 10 and 12, then Q + S = 20. This is still too small, but it's getting closer to 24...

IF Q, R and S are....
10, 12 and 14, then Q + S = 24. This is a MATCH for what we're looking for. We can also figure out the missing values (they're 8 and 16).

By making these variables larger or smaller, the sum of Q+S won't = 24, so we know that the 10/12/14 example is the ONLY possibility that fits.
Fact 1 is SUFFICIENT.

Fact 2: The average of Q and R is 11

Since Q and R are 2 CONSECUTIVE EVEN INTEGERS, we're going to need 2 numbers that are close to 11....

IF Q and R are....
8 and 10, then the average is 9 (which is not a match; it's supposed to be 11)

IF Q and R are...
10 and 12, then the average is 11. This is a MATCH.

Making Q and R any bigger will raise the average (and it won't match), so we know that 10 and 12 are the ONLY possible values that fit. The other numbers would be 8, 14 and 16.
Fact 2 is SUFFICIENT.

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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 14 May 2016, 04:56
Walkabout wrote:
Attachment:
Number line.png
On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24
(2) The average (arithmetic mean) of q and r is 11.


Solution:

Let’s begin by sketching the number line.

Image

We need to determine whether r is closest to zero.

Statement One Alone:

q = -s

Since q = -s, q and s are opposites. For example, q = 2 and s = -2, or, q = -3 and s = 3. However, since q is to the left of s, q must be negative and s must be positive. Because q and s are opposites, zero must be exactly halfway between q and s. Since variable r is also between q and s we know that r is closer to zero than any other variable on our number line.

Statement one is sufficient to answer the question. We can eliminate answer choices B, C, and D.

Statement Two Alone:

-t < q

Since statement two is comparing the possible values of –t and q with an inequality, we do not have any significant information that will allow us to determine an exact location of zero on the number line. For example, if q = 1, r = 2, s = 3 and t = 4, then q is closer to 0 than r is. If q = -1, r = 0, s = 1, and t = 2, then r is closest to 0 since r itself is 0. Since we can have two contradictory scenarios, statement two does not provide enough information to answer the question.

The answer is A.
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 01 Apr 2017, 09:41
Walkabout wrote:
Attachment:
Number line.png
On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24
(2) The average (arithmetic mean) of q and r is 11.



Given:
CONSECUTIVE EVEN INTEGERS
p=2n
q=2n+2
r=2n+4
s=2n+6
t=2n+8

p<q<r<s<t

Mean= (2n+2n+2+2n+4+2n+6+2n+8)/5
= (10n+20)/5
=10(n+2)/5
=2(n+2)


(1) q+s=24
2n+2+2n+6=24
One variable thus can be solved.

Sufficient.

AD

(2) Mean= (2n+2+2n+4)/2

One variable thus can be solved.

D
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 19 Jul 2017, 08:23
STatement 1 no. of terms is 5 so the center term i.e r will be the avg as the series is an Arithmetic progression
so it can be found by (q +s)/2 = 12.

Statement 2 : given :- (q + r) / 2 = 11.
also q = r-2 (as all are even consecutive integers in a series.)
So again the avg can be found out.

Answer D
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 17 Aug 2017, 02:07
1) q+s=24
p,q,r,s,t

s-q= 4 and s+q =24. add them. s=14 and series will be 8,10,12,14,16 and mean will be 12. sufficient A/D can be answer

2) mean of q and r is 11, q+r=22.
r+q=22 , r-q =2 add them r=12, and series will be again same and same answer as above therefore sufficient

D is answer
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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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New post 18 Aug 2017, 23:44
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Attachment:
Number line.png
On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24

As we know that r is the median of q and s, and r is also the median of p,q,r,s, and t. Hence, if we know the value of r we should be able to answer the question.

q + s = 24

Midpoint = 24/2 = 12 = r

Hence, (1) ===== is SUFFICIENT

(2) The average (arithmetic mean) of q and r is 11

q = r - 2

r - 2 + r = 11 * 2

2r = 24

r = 12

Hence, (2) ===== is SUFFICIENT

Hence, Answer is D

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Re: On the number line above, p, q, r, s, and t are five consec  [#permalink]

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