peachfuzz wrote:

If xy < 0, is x/y > z ?

2 scenarios

x is neg and y is pos

x is pos and y is neg

(1) xyz < 0

x is neg, y pos, z pos

x is pos, y neg, z pos

Both scenarios make z larger than x/y

Sufficient

(2) x > yz

x is neg, y pos, z neg

X is pos, y negative, z pos

If z is neg the question is yes

If z is positive question is no

Insufficient

Answer: A

I'm just talking about the red part..

In the question stem: if xy<0, then

x-->(+)

y-->(-)

or,

x-->(-)

y-->(+)

If z is negative, the answer can't be YES always.

Here is test cases:

suppose,

x=-10

y=5

and z=-6

then, x/y>z?

-->-10/5>-6?

-->-2>-6?

--> YES

But, if

x=-10

y=5

and z=-1,

then, x/y>z?

-->-10/5>-1?

-->-2>-1?

-->NO....

Am I right

Bunuel?

Thank you brother...

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