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24 Sep 2025, 07:32
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4^(4^4) = 2^(2.4^4) = 2^(2*2^8) = 2^(2^9). Equating it with 2^2^x, we get x = 9
24 Sep 2025, 07:43
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Discussed here: if-x-is-a-real-number-and-4-4-4-2-2-x-what-is-426425.html
If x is a real number and \(4^{(4^{4})} = 2^{(2^x)}\), what is the value of x ?
A. 7
B. 8
C. 9
D. 16
E. 256
\(4^{(4^{4})} = 2^{(2^x)}\)
\((2^2)^{((2^2)^{4})} = 2^{(2^x)}\)
\((2^2)^{(2^8)} = 2^{(2^x)}\)
\(2^{2*2^8} = 2^{(2^x)}\)
\(2^{2^9} = 2^{(2^x)}\)
\( x = 9\)
Answer: C.
If x is a real number and \(4^{(4^{4})} = 2^{(2^x)}\), what is the value of x ?
A. 7
B. 8
C. 9
D. 16
E. 256
\(4^{(4^{4})} = 2^{(2^x)}\)
\((2^2)^{((2^2)^{4})} = 2^{(2^x)}\)
\((2^2)^{(2^8)} = 2^{(2^x)}\)
\(2^{2*2^8} = 2^{(2^x)}\)
\(2^{2^9} = 2^{(2^x)}\)
\( x = 9\)
Answer: C.
